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metallicafan
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04 Nov 2010, 08:41
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
77% (02:20) correct
23%
(02:40)
wrong
based on 663
sessions
History
Date
Time
Result
Not Attempted Yet
In ten years, David will be four times as old as Aaron. Twenty years ago, David was twice as old as Ellen. If David is seven years older than Ellen, how old is Aaron?
A. 1-5
B. 6-10
C. 11-15
D. 16-20
E- 21-25
A. 1-5
B. 6-10
C. 11-15
D. 16-20
E- 21-25
04 Nov 2010, 09:33
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metallicafan
In ten years, David will be four times as old as Aaron --> \(D+10=4(A+10)\);
Twenty years ago, David was twice as old as Ellen --> \(D-20=2(E-20)\) --> \(D+20=2E\);
David is seven years older than Ellen (now) --> \(D-7=E\);
Subtract 3 from 2: \(D+20-(D-7)=2E-E\) --> \(E=27\) and \(D=34\) --> \(D+10=34+10=4(A+10)\) --> \(A=1\);
So, \(A=1\), \(E=27\), and \(D=34\).
Answer: A.
General Discussion
22 Jul 2015, 09:14
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Hi Bunnuel,
i still have a hard time trying to figure out your process how did you go from D+20-(D-7)=2E-E to E=27 and D=34 ?
i noticed in other similar age questions you tend to do the same process but this is the part where you lose me.
could you go step by step pls
thanks!!!
i still have a hard time trying to figure out your process how did you go from D+20-(D-7)=2E-E to E=27 and D=34 ?
i noticed in other similar age questions you tend to do the same process but this is the part where you lose me.
could you go step by step pls
thanks!!!
