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rtaha2412
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My guess is E.

Six machines can do 1/8 of the job within an hour. => 1 machine can do 1/48 of the job within a hour. => 5 machines can do 5/48 of the job within a hour.

=> 5 machines can do a full job in 48/5 hours.

The difference between 48/5 hours and 5 hours is 8/5, which is 96 minutes (the answer to the question).
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I agree with E

start with x/6=8 so x = 48

next divide 48/5 which =9.6

so it takes 9.6 hours but you need to convert that to minutes so .6=36 mins so it takes 1 hour and 36 mins more or 96 mins. so E
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rtaha2412
If 6 machines run at the same constant rate, they can complete a job in 8 hours. If only 5 of these machines run at this rate, how many more minutes will be required to complete the same job?

A. 38
B. 72
C. 80
D. 90
E. 96

The question can be answered in 30 sec if you have a fundamental understanding of simple principle:
Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance in rate problems.

\(time*speed=distance\) <--> \(time*rate=job \ done\).

So, if you decrease the rate of work 5/6 times (from 6 to 5 machines) the time needed to complete the same job will increase 6/5 times.

Time needed for 6 machines = 80*60 = 480 minutes;
Time needed for 5 machines = 480*6/5 = 576 minutes;

Difference: 576-480=96 minutes.

Answer: E.

For more on Work/Rate Problems check this: two-consultants-can-type-up-a-report-126155.html#p1030079

Hope it helps.
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rtaha2412
If 6 machines run at the same constant rate, they can complete a job in 8 hours. If only 5 of these machines run at this rate, how many more minutes will be required to complete the same job?

A. 38
B. 72
C. 80
D. 90
E. 96

On the same lines as Bunuel.
The new rate is 5/6 of the earlier. The new total time will be 6/5 of original.
To get the extra time 6/5 - 1 = 1/5. It will take 1/5 (20%) of original time to complete the same task. 1/5 * 480 = 96mins
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if 6 machines need 8 h, then 1 machine needs 6*8=48 hours

48/5 -8=9 3/5-8=8/5 h

8/5h*60=96
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Setup the rate equation for 6 machines working for 8 hours to finish a job:
\((\frac{1}{m}+\frac{1}{m}+\frac{1}{m}+\frac{1}{m}+\frac{1}{m}+\frac{1}{m})(8hours)=1==>m=48hours\)

Setup the rate equation for 5 machines to finish the same job:
\(\frac{5}{48}t=1==>t=\frac{48}{5}=9.6hours\)

ANswer: 9.6 - 8 = 1.6 hours or 96 minutes (E)
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rtaha2412
If 6 machines run at the same constant rate, they can complete a job in 8 hours. If only 5 of these machines run at this rate, how many more minutes will be required to complete the same job?

A. 38
B. 72
C. 80
D. 90
E. 96

6 machine rate = 1/8
1 machine rate = 1/48
5 machine rate = 5/48

Rate x Time = Job

5/48 x T = 1
T= 48/5 = 9.6 > 9 hour 36 minutes

so extra time = 9 Hour 36 minutes - 8 hour = 1 hour 36 minute = 96 minutes

answer E
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6m....1job...8hrs
5m....1job...xhrs
x=8*6/5
x=48/5 (convert to hrs)
9hrs 36 Mins which is 1hr 36 Mins more (convert the extra time into mins) =96 Mins
Option E
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One machine needs to complete 6*8=48 hour. Suppose, total units = 48.
so 5 machines done 5*8=40hour.
Remaining 8 units is done 8÷5*60=96 minute.

Posted from my mobile device
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Fijisurf
My guess is E.

Six machines can do 1/8 of the job within an hour. => 1 machine can do 1/48 of the job within a hour. => 5 machines can do 5/48 of the job within a hour.

=> 5 machines can do a full job in 48/5 hours.

The difference between 48/5 hours and 5 hours is 8/5, which is 96 minutes (the answer to the question).

why do you take the difference from 5 hours? I got everything up until that point, can you please explain
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Use this ,

W1 / (M1 * T1 ) = W2 / (M2 * T2)

=> 1 / 6 * 8 = 1 / 5 * T2

=> T2 = 9.6 hours

Hence , (9.6-8.0) = 1.6 hours = 96 minutes more will be required.­
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Total number of units produced by 6 machines : 6 * 8 = 48
Total number of units produced by 5 machines : 5 * 8 = 40

Number of units left to be produced by 5 machines : 48 - 40 = 8

Number of minutes it will take to produce 8 units by 5 machines : ( 8 * 60 ) / 5 = 96 minutes
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