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monirjewel
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In the xy plane, the vertices of a triangle have coordinates Updated on: 31 Oct 2016, 23:23
Originally posted by monirjewel on 28 Oct 2010, 22:18.
Last edited by Bunuel on 31 Oct 2016, 23:23, edited 1 time in total.
Renamed the topic.
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In the xy-plane, the vertices of a triangle have coordinates (0,0),(3,3), and (7,0). What is the perimeter of the triangle?

(A) 13
(B) (14)
(C) (16)
(D) (17)
(E) 12+3 root 2

How to draw graph on this?
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E
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Bunuel
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In the xy plane, the vertices of a triangle have coordinates 05 Nov 2010, 21:08
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monirjewel
In the xy plane, the vertices of a triangle have coordinates(0,0), (3,3), and (7,0). What is the perimeter of the triangle?
(A) 13
(B) 34
(C) root 43
(d) 7+root3
(E) 12 +3root2
Show more

The formula to calculate the distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\).

Distance between (0, 0) and (7, 0) is \(d=7\);
Distance between (0, 0) and (3, 3) is \(d=\sqrt{(0-3)^2+(0-3)^2}=\sqrt{18}=3\sqrt{2}\);
Distance between (3, 3) and (7, 0) is \(d=\sqrt{(3-7)^2+(3-0)^2}=5\);

\(P=7+3\sqrt{2}+5=12+3\sqrt{2}\).

Answer: E.

For more check Coordinate Geometry chapter of Math Book: math-coordinate-geometry-87652.html

Hope it helps.
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In the xy plane, the vertices of a triangle have coordinates 14 Nov 2016, 07:09
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monirjewel
In the xy-plane, the vertices of a triangle have coordinates (0,0),(3,3), and (7,0). What is the perimeter of the triangle?

(A) 13
(B) (14)
(C) (16)
(D) (17)
(E) 12+3 root 2

How to draw graph on this?
Show more

Plot the graph and you will get two triangles one is pythagorean triples(3, 4, 5) and 3, 3, and 3sqrt(2)

by this perimeter is 12+3sqrt(2)
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In the xy plane, the vertices of a triangle have coordinates 29 Oct 2010, 00:27
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Moving to PS sub-forum ...


!
Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/
Please post DS questions in the DS subforum: gmat-data-sufficiency-ds-141/

To answer this question ... all you need is distance between vertices :

(0,0) & (7,0) : 7
(0,0) & (3,3) : \(3\sqrt{2}\)
(7,0) & (3,3) : \(\sqrt{16+9}=5\)

Perimeter = sum of these three sides = \(12 + 3\sqrt{2}\)

Answer : e
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In the xy plane, the vertices of a triangle have coordinates 05 Nov 2010, 20:31
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In the xy plane, the vertices of a triangle have coordinates(0,0), (3,3), and (7,0). What is the perimeter of the triangle?

(A) 13
(B) 34
(C) root 43
(D) 7+root3
(E) 12 +3root2
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In the xy plane, the vertices of a triangle have coordinates 03 Jan 2013, 04:10
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monirjewel
In the xy plane, the vertices of a triangle have coordinates(0,0), (3,3), and (7,0). What is the perimeter of the triangle?
(A) 13
(B) 34
(C) root 43
(d) 7+root3
(E) 12 +3root2
Show more

Get distance between (0,0) and (3,3): \(\sqrt{(3 - 0)^2 + (3-0)^2} = \sqrt{(18)} = 3 \sqrt{(2)}\)
Get distance between (3,3) and (7,0): \(\sqrt{(7-3)^2 + (3-0)^2} = \sqrt{16 + 9}= \sqrt{25}=5\)
Get distance between (0,0) and (7,0): 7

\(P = 7 + 5 + 3\sqrt{2} = 12 + \sqrt{2}\)

Answer: E
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In the xy plane, the vertices of a triangle have coordinates 31 Jul 2016, 02:15
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Hi Bunnuel,

Is there any formula to calculate area of triangle when all coordinates are known?

Please help. Many thanks in advance for your kind response

Regards
Megha
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In the xy plane, the vertices of a triangle have coordinates 31 Jul 2016, 02:25
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megha_2709
Hi Bunnuel,

Is there any formula to calculate area of triangle when all coordinates are known?

Please help. Many thanks in advance for your kind response

Regards
Megha
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I really doubt that you'll need it for the GMAT but here you go:

If the vertices of a triangle are: \(A(a_x, a_y)\), \(B(b_x, b_y)\) and \(C(c_x,c_y)\) then the area of ABC is:

\(area=|\frac{a_x(b_y-c_y)+b_x(c_y-a_y)+c_x(a_y-b_y)}{2}|\).
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In the xy plane, the vertices of a triangle have coordinates 01 Aug 2016, 13:42
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Bunuel
megha_2709
Hi Bunnuel,

Is there any formula to calculate area of triangle when all coordinates are known?

Please help. Many thanks in advance for your kind response

Regards
Megha

I really doubt that you'll need it for the GMAT but here you go:

If the vertices of a triangle are: \(A(a_x, a_y)\), \(B(b_x, b_y)\) and \(C(c_x,c_y)\) then the area of ABC is:

\(area=|\frac{a_x(b_y-c_y)+b_x(c_y-a_y)+c_x(a_y-b_y)}{2}|\).
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Ohh,

A day before I saw question like that on gmat club. Anyways many thanks for your response and telling me its highly unlikely to come. :)

Regards
Megha
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In the xy plane, the vertices of a triangle have coordinates 31 Oct 2016, 17:09
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Relatively straight-forward problem, though I'd suggest plotting it so you can visualize the sides and what two side lengths you will need to calculate.

Base length is 7

(1) Distance between (0,0) & (3,3) --> sqrt[(3^2)+(3^2)] = 3sqrt(2)

(2) Distance between (3,3) & (7,0) --> sqrt[(3-0)^2 + (3-7)^2] = sqrt(9+16) = sqrt(25) =5

Add them all up --> 12+ 3sqrt(2)

E
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In the xy plane, the vertices of a triangle have coordinates 27 May 2020, 00:04
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An efficient way of solving this problem is by recalling common sides of a triangle.

- We know that the length of one of the sides is 7 simply because it's the distance between coordinates (0,0) and (7,0).

- We can split the triangle into 2 smaller triangles
--> Triangle 1 coordinates (0,0), (3,3) and (3,0)
--> Triangle 2 coordinates (3,0), (3,3) and (7,0)

- Triangle 1 has sides that appear to be very similar to the common triangle with sides (1):(1):(√2). In fact, its sides can be written as (3):(3):(3√2) and now we know that one side of the original triangle is (3√2).

- Triangle 2 has sides that are exactly the same as the common triangle with sides (3):(4):(5) and now we know that one side of the original triangle is (5).


Our perimeter is (7) + (3√2) + (5) = 12 +3√2

Looking at the answer choices, we can also tell that the only answer choice that contains (3√2) is answer choice E
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In the xy plane, the vertices of a triangle have coordinates 04 Oct 2025, 06:41
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