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14 Feb 2011, 15:52
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (02:02) correct
30%
(02:21)
wrong
based on 722
sessions
History
Date
Time
Result
Not Attempted Yet
How many integers from 1 to 200, inclusive, are divisible by 3 but not divisible by 7?
(A) 38
(B) 57
(C) 58
(D) 60
(E) 66
(A) 38
(B) 57
(C) 58
(D) 60
(E) 66
14 Feb 2011, 16:14
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banksy
We should find # of integers divisible by 3 but not by 3*7=21.
# of multiples of 3 in the range from 1 to 200, inclusive is (198-3)/3+1=66 (check this: totally-basic-94862.html);
# of multiples of 21 in the range from 1 to 200, inclusive is (189-21)/21+1=9;
66-9=57.
Answer: B.
General Discussion
jlgdr
Joined: 06 Sep 2013
Last visit: 24 Jul 2015
Posts: 1,302
Given Kudos: 355
Concentration: Finance
Schools: Wharton '17 (A) HBS '17 (WA$)
25 Nov 2013, 08:18
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banksy
We need to find the multiples of 3 and subtract the multiples of 21.
So in 21 numbers we have 7 multiples of 3 - 1 multiple of 21 = 6 total
In the selected range we have 9 sets of 21 = 198 and three more multiples of three none of which is a multiple of 7 (192, 195 and 198)
So in total we have (9*6) + 3 = 57
Answer is B
Hope it helps
Cheers!
J
