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Yalephd
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Patanahi, how do you use -(x-6) (x+2) to eliminate answer choices A, B, D & E? Do you have to set -(x-6) (x+2) = to each choice and test them?

patanahi
The three number can be X, X+2, x+4

s^2- r^2 - q^2
(X+4)^2 - (x+2)^2 - x^2
X^2 + 8X + 16 - X^2 - 4X - 4 - X^2
-X^2 - 4x + 12
-(x-6) (x+2)

Answer "C" can not be the value.
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testing for the blocks -4,-2,0 ; -2,0,2; 0,2,4 and 2,4,6 eliminates -20,0,12 and 16 respectively.

well a quick approach is to check the min and the max values here which are -20 and 16. This will give the range of even numbers to be tested.

I did the same and just kept shifting the window.
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s^2- r^2 - q^2 = (q+4)^2- (q+2)^2 - q^2

= q^2 + 16 + 2*4*q - (q^2 + 2*2q + 4) - q^2

= -q^2 + 12 + 4q

All except 8 fit in this.

Answer - C
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Assuming the numbers to be
2n, 2n+2, 2n+4
then substituting the values if expression s2-r2-q2 gives a quadratic equation which can be simplified as follows

-4(n+1)(n-3)
n=1,2,3,4
16 ,12,0,-20
eliminating 8 as the answer. So choice C
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