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cleetus
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A motorcyclist has to cover a distance of 200 km to reach 16 Aug 2011, 18:46
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85% (hard)

Question Stats:

36% (03:03) correct 64% (03:13) wrong based on 29 sessions

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A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A. 50KM,60KM
B. 40KM, 40KM
C. 60KM, 30KM
D. 50KM, 50 KM
E. 60KM 60KM
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D
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A motorcyclist has to cover a distance of 200 km to reach 16 Aug 2011, 21:43
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cleetus
A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A) 50KM,60KM
B) 40KM, 40KM
C)60KM, 30KM
D)50KM, 50 KM
E) 60KM 60KM
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This is beyond GMAT because it is more laborious and less logical.

Let the initial breakdown occurred at x km
Let the initial speed be v km/h

\(\frac{x}{v}+\frac{200-x}{\frac{3}{4}v}=\frac{200}{v}+1\) ------------------1

\(\frac{x-30}{v}+\frac{200-(x-30)}{\frac{3}{4}v}=\frac{200}{v}+1+\frac{1}{5}\) ------------------2

Solve these equations to get x and v.

Ans: "D"
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A motorcyclist has to cover a distance of 200 km to reach 17 Aug 2011, 06:39
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um so happy to read it's beyond GMAT...wish n hope such ques nvr cum
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A motorcyclist has to cover a distance of 200 km to reach 25 Aug 2012, 12:01
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A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

we can use options to solve this poblem.

D) 50 KM , 50 KM

Ist part says if he travels 3/4 th of original speed he reaches 1 hour late.

3/4 th speed of 50 = 37.5

if 50 KM is already covered as in option, total time taken at reduced speed to cover remaining distance.

150 / 37.5 = 4
total time = 4 + 1 = 5

and if he has travelled at original speed , time taken
= 200/ 50 = 4

Thus, the difference = 1 hour. In all the remaining case the difference of time is not 1 hour.

Answer D.
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A motorcyclist has to cover a distance of 200 km to reach 25 Aug 2012, 12:58
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fluke
cleetus
A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A) 50KM,60KM
B) 40KM, 40KM
C)60KM, 30KM
D)50KM, 50 KM
E) 60KM 60KM

This is beyond GMAT because it is more laborious and less logical.

Let the initial breakdown occurred at x km
Let the initial speed be v km/h

\(\frac{x}{v}+\frac{200-x}{\frac{3}{4}v}=\frac{200}{v}+1\) ------------------1

\(\frac{x-30}{v}+\frac{200-(x-30)}{\frac{3}{4}v}=\frac{200}{v}+1+\frac{1}{5}\) ------------------2

Solve these equations to get x and v.

Ans: "D"
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This is the advantage of multiple choice questions...:o)

The first equation gives \(3v+x=200.\) The second equation boils down to \(18v+5x=1150.\)
You can try to pick the correct answer based on the first equation and even before you work out the second equation. They can't be so mean to provide more than one solution which fulfill the first equation. Or let's hope...:o)
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A motorcyclist has to cover a distance of 200 km to reach 27 Aug 2012, 08:28
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Why not solve this problem in different way ?

Distance................: A...............................................B
Velocity..................: V...............l....3V/4..................... (this takes +1 hr)
If 30 KM before......: V.........l..........3V/4............................ (this takes +1 hr + 12 minutes)

So, we can deduce that as the cyclist lowered the speed from V to 3V/4 to cover 30 KM, he tool 12 minutes more time.

So, forming equation to find the difference of time we get we get

\(30*4/3V - 30/V = 12\)
\(=> 40/V - 30/V=12\)
\(=> 10/V=12\)
\(=> V=10 KM/12 Minutes\)
\(=> V=50 KM/Hr\)

Only option D has this value. So, it is the right answer
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A motorcyclist has to cover a distance of 200 km to reach 11 Jan 2019, 22:49
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cleetus
A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A. 50KM,60KM
B. 40KM, 40KM
C. 60KM, 30KM
D. 50KM, 50 KM
E. 60KM 60KM
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A simpler approach to the question

the motorcyclist travels at 3/4th of speed and gets late by 1 hours

the motorcyclist travels 30km more at 3/4th of speed and gets late by 1 hours and 12 mins

i.e. the motorcyclist travels 30 km at 3/4th of speed and gets late by 12 mins

i.e. to be late by 60 mins i.e. 1 hour (12*5) he has to travel 150 km (30*5) at 3/4th of usual speed

hence, he travels the distance of 200-150 = 50 km at regular speed before the breakdown

Now, the motorcyclist travels at 3/4th of speed and gets late by 1 hours

Since D = S*T
therefore, D = (3/4)S*(4/3)T . (to nullify the effect of 3/4 in speed we need to multiply the time by 4/3 so that the distance remains same)

i.e. extra time consumed due to reduced speed = (4/3)T - T = (1/3)*T = 1 hour

i.e. T = 3 hours

to travel the distance 150 km (distance after breakdown) in 3 hours (regular time to travel the distance 150 km), Speed = 150/3 = 50 km/hr

Answer: Option D
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A motorcyclist has to cover a distance of 200 km to reach 10 Jan 2021, 09:45
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