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Agreed.

This is a problem where you need to consider worst case:

1. Take out 4 Dramas.
2. Take 5 of each of the other 3, total of 15.
3. Next book you take will complete a set of 6.

Total is 4+15+1 = 20.

A
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There are 9 novel books, 4 drama books, 12 poetry books and 7 grammar books in my bookshelf. The books are randomly arranged in the shelf and not at all in the order of their type. What is the least number of books that must be drawn from the shelf in order to get 6 books of a particular type?

a) 20
b) 23
c) 25
d) 28
e) None of these

Let’s assume the worst case scenario. Let’s say we have drawn 5 novels, all 4 drama books, 5 poetry books, and 5 grammar books; we would have a total of 19 books drawn but still not have 6 books of one type. However, if we draw just one more book (which must be a novel, poetry, or a grammar book), we would have 6 books of one particular type. Thus, the least number of books that must be drawn is 20.

Answer: A
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I still do not understand. Can anyone please give more explaination on this question?
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How would the answer change if it instead asked: What is the least number of books that must be drawn from the shelf in order to get 6 books of any type?
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How would the answer change if it instead asked: What is the least number of books that must be drawn from the shelf in order to get 6 books of any type?
That would mean the saem thing and the answer would be the same. We cannot guarantee getting 6 books of any kind in fewer than 20 picks.
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What is the significance of "not at all in the order of their type"?
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