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kiran882
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Bunuel


Since xyz is an even number then it's \(532=2^2*7*19\) or \(352=2^5*11\).

In either case the # of factors is 12:
For \(532=2^2*7*19\) the # of factors will be \((2+1)(1+1)(1+1)=12\);
For \(352=2^5*11\) the # of factors will be \((5+1)(1+1)=12\).

Answer: C.


Why answer cannot be E-24. We have 2 even numbers 532 and 352. Both are giving 12 as # of factors. Question asks, Find the number of factors of a three digit even number xyz ? So, Can't we consider both the even numbers ?

No. Find the number of factors of a three digit even number xyz. xyz is one number.
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Bunuel

No. Find the number of factors of a three digit even number xyz. xyz is one number.

Okay. Got it. Thanks
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kiran882
Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

Since xyz is an even number then it's \(532=2^2*7*19\) or \(352=2^5*11\).

In either case the # of factors is 12:
For \(532=2^2*7*19\) the # of factors will be \((2+1)(1+1)(1+1)=12\);
For \(352=2^5*11\) the # of factors will be \((5+1)(1+1)=12\).

Answer: C.

In case one doesn't know.
Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

For more on number properties check: math-number-theory-88376.html

Hope it helps.


Hi Bunuel.
I have a doubt in the highlighted part.

The question says -> x, y and z are distinct prime numbers (2, 3 and 5)
So shouldn't x,y,z be 2,3,5 respectively?
Why would they write x,y,z and then mention 2,3,5 against them.
Wouldn't GMAT specify the same?


Though the answer would not be affected but i guess a clarification would be helpful in similar questions.

Regards
Stone Cold.
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kiran882
Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

So the following numbers can be possible
235, 532, 352

Take factors of 1 of them
532 = 2*2*7*19

2^3 * 7^2 * 19^2

12

C
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kiran882
Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

Since xyz is even and x, y, and z are distinct prime numbers (2, 3, and 5), xyz can either be 352 or 532.

Recall that to determine the number of factors of a number, we add 1 to each exponent of its prime factorization and then multiply those numbers.

If xyz = 352 = 4 * 88 = 2^2 * 2^3 * 11 = 2^5 * 11, then it has (5 + 1) * (1 + 1) = 6 * 2 = 12 factors.

If xyz = 532 = 4 * 133 = 2^2 * 7 * 13, then it has (2 + 1) * (1 + 1) * (1 + 1) = 3 * 2 * 2 = 12 factors.

Therefore, we can see that either way, xyz has 12 factors.

Answer: C
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