Last visit was: 24 Apr 2026, 02:47 It is currently 24 Apr 2026, 02:47
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
newC
Joined: 06 Mar 2012
Last visit: 07 Mar 2012
Posts: 2
Own Kudos:
9
 [9]
Posts: 2
Kudos: 9
 [9]
1
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,802
Own Kudos:
810,921
 [5]
Given Kudos: 105,868
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,802
Kudos: 810,921
 [5]
3
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
avatar
joshuaRome
Joined: 13 Jan 2012
Last visit: 19 Jun 2012
Posts: 2
Posts: 2
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
newC
Joined: 06 Mar 2012
Last visit: 07 Mar 2012
Posts: 2
Own Kudos:
Posts: 2
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Thanks a lot :)

I was stuck at that point, that k=o, because passing through the origin
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,802
Own Kudos:
Given Kudos: 105,868
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,802
Kudos: 810,921
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bumping for review and further discussion.
User avatar
atalpanditgmat
Joined: 02 Oct 2012
Last visit: 15 Nov 2013
Posts: 68
Own Kudos:
711
 [4]
Given Kudos: 23
Status:Working hard to score better on GMAT
Location: Nepal
Concentration: Finance, Entrepreneurship
GPA: 3.83
WE:Accounting (Consulting)
Posts: 68
Kudos: 711
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
newC
In the xy plane line m has the equation 4x + y = k. Line n passes through the origin and is perpendicular to line m. If point p has the coordinates (r, r+1) and is on both line n and m what is the value of r?

A. -4/3
B. 1/4
C. -4
D. 3/4
E. 4/3

Can anybody help me with this problem?! I really have no idea how to attack this problem..
Thanks!!

You can approach by calculating slopes of both lines m and n.

As we know both m and n lines are perpendicular; slope m* slope n= -1

slope of m= -4 since 4x=y+k =>(Y=mx+c), where m is slope

now calculate slope of n. as we know line passes through origin (0,0) and (r, r+1)

slope = (y2-y1)/(x2-x1) => (r+1-0)/(r-0) => (r+1)/r

lines are perpendicular; thus we can multiply both slopes

(r+1)/r*-4=-1 gives r= -4/3

Hence Ans is A.

Hit Kudos if you like it... :-D
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,890
Kudos
Add Kudos
Bookmarks
Bookmark this Post
newC
In the xy plane line m has the equation 4x + y = k. Line n passes through the origin and is perpendicular to line m. If point p has the coordinates (r, r+1) and is on both line n and m what is the value of r?

A. -4/3
B. 1/4
C. -4
D. 3/4
E. 4/3

Can anybody help me with this problem?! I really have no idea how to attack this problem..
Thanks!!

Two perpendicular lines with slopes m1 and m2 are such that m1*m2 = -1

Given that lines m and n are perpendicular to each other ---> slope of n = -1/slope of line m = -1/-4 = 1/4

Also, line n passes through (0,0) ---> y = ax+b ---> b=0 and a =1/4 --> equation of line n = y =x/4

Now as point (r,r+1) lies on n , substitute y=r+1 and x=r --> 4(r+1)=r --> 4r+4 = r --> 3r=-4 --> r = -4/3.. A is the correct answer.
User avatar
TeamGMATIFY
Joined: 20 Aug 2015
Last visit: 31 Oct 2016
Posts: 339
Own Kudos:
Given Kudos: 10
Location: India
GMAT 1: 760 Q50 V44
Expert
Expert reply
GMAT 1: 760 Q50 V44
Posts: 339
Kudos: 1,527
Kudos
Add Kudos
Bookmarks
Bookmark this Post
newC
In the xy plane line m has the equation 4x + y = k. Line n passes through the origin and is perpendicular to line m. If point p has the coordinates (r, r+1) and is on both line n and m what is the value of r?

A. -4/3
B. 1/4
C. -4
D. 3/4
E. 4/3


Given:
Line m: 4x + y = k Or y = -4x + k
Line n passes through (0,0) and is perpendicular to line m

If two lines are perpendicular, then the product of their slopes = -1

Hence slope of line n = 1/4

Equation of line n:
y - 0 = 1/4(x-0)
y = x/4

Point p lies on the line n
Hence: r+1 = r/4,
4r + 4 = r
r = -4/3
Option A
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,966
Own Kudos:
Posts: 38,966
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109802 posts
Tuck School Moderator
853 posts