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02 Jun 2012, 23:51
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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82% (02:18) correct
18%
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based on 744
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A pool which was 2/3 full to begin with, was filled at a constant rate for 5/3 hours until it was until it was 6/7 full. At this rate, how much time would it take to completely fill this pool if it was empty to begin with?
A. 8 hrs 45 mins.
B. 9 hrs.
C. 9 hrs 30 mins.
D. 11 hrs 40 mins.
E. 15 hrs 30 mins .
A. 8 hrs 45 mins.
B. 9 hrs.
C. 9 hrs 30 mins.
D. 11 hrs 40 mins.
E. 15 hrs 30 mins .
14 Nov 2012, 05:07
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Calculate the rate of the pipe:
\(Output = \frac{6}{7}-\frac{2}{3}=\frac{4}{21}\)
\(t = \frac{5}{3} hours\)
\(R = \frac{Output}{t} = 4/35\)
time it takes to fill the pool = reciprocal of rate
\(\frac{35}{4}hours = 8 \frac{3}{4}hours = 8 hours and 45 minutes\)
\(Output = \frac{6}{7}-\frac{2}{3}=\frac{4}{21}\)
\(t = \frac{5}{3} hours\)
\(R = \frac{Output}{t} = 4/35\)
time it takes to fill the pool = reciprocal of rate
\(\frac{35}{4}hours = 8 \frac{3}{4}hours = 8 hours and 45 minutes\)
General Discussion
03 Jun 2012, 02:56
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A.
The pool was 2/3 full initially.
In 5/3 hrs, it was filled to 6/7 of its capacity.
Therefore, in 5/3 hrs, 6/7 - 2/3 was the amount of volume filled.
So, 5/3 hrs = 6/7 - 2/3 = 4/21
Therefore, for filling the vessel from empty to full, you would require 5/3 * 21/4 = 35/4 = 8 Hrs 45 Mins.
Hence A
The pool was 2/3 full initially.
In 5/3 hrs, it was filled to 6/7 of its capacity.
Therefore, in 5/3 hrs, 6/7 - 2/3 was the amount of volume filled.
So, 5/3 hrs = 6/7 - 2/3 = 4/21
Therefore, for filling the vessel from empty to full, you would require 5/3 * 21/4 = 35/4 = 8 Hrs 45 Mins.
Hence A
