watwazdaquestion
Vips0000
vomhorizon
The sum of the digits of a two digit number is 10. When the digits are reversed, the number decreases by 54. Find the changed Number.
(A) 28
(B) 19
(C) 37
(D) 46
Let the Units digit of the Number be Y and the Tens digit be X. The number can be represented as 10X + Y
According to the Question Stem: X + Y = 10
When the number is reversed we get 10Y+X as the new number.
According to the question stem: (10x+Y) - (10 Y + X) = 54 , Simplifying we get 9X - 9Y = 54 or 9 (X-Y) = 54 or X-Y = 6.
Putting this in the original equation we get two equations ; X + Y = 10 (1) and X - Y = 6 (2)
Solving 1 & 2 we get X = 8. Y comes out to 2 , and the Original Number is 82. The new number is 28 (A)
Reversing digits gives a number 54 less than original => difference in digits =54/9 = 6
Only option A satsifies this.
Ans A it is.
Can you further explain this in detail? How did you get 54/9 ? Where did the 9 come from?
This 9 is logical derivation. Difference between a 2 digit number and number with reversed digit is always 9 times the difference between digits.
Any number 10a+b when reversed would be 10b+a , the difference would be 9(b-a)