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505-555 (Easy)|   Algebra|                        
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290=\frac{5}{9}(K-32)
58*9=k-31
i rounded 9 to 10 so
580-58+31=k
then i choose d, no point in doing calculations to waste time
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Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...
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Walkabout
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

We start by substituting 290 for T and we obtain:

290 = 5/9(K – 32)

To eliminate the fraction, we multiply the entire equation by 9 and we have:

290 x 9 = 5(K – 32)

We next divide both sides by 5 and then solve for K:

58 x 9 = K – 32

522 = K – 32

554 = K

The answer is D.
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Walkabout
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

\(T = \frac{5}{9} * (K - 32)\)
As T = 290

290 = \(T = \frac{5}{9} * (K - 32)\)
Solving we have
58*9 + 32 = K

Here we can see that it would result in 500+ something value so answer should be D.

Beside the unit value of 58*9 + 32 is '4' just in case we need to verify.

Answer D.
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Walkabout
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

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