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22 Jun 2013, 05:47
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
65% (01:50) correct
35%
(01:45)
wrong
based on 486
sessions
History
Date
Time
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Not Attempted Yet
5 and 15 are the first two terms in a geometric sequence. What is the arithmetic difference between the 11th term and the 13th term?
A. 3*5^2
B. 5* 3^13 - 5 * 3^11
C. 5^13
D. 40 * 3^10
E. 3^12 - 3^10
A. 3*5^2
B. 5* 3^13 - 5 * 3^11
C. 5^13
D. 40 * 3^10
E. 3^12 - 3^10
Question regarding arithmetic difference is a - b / 2? or only a - b?
arpanpatnaik
GMAT 1: 640 Q42 V37
Posts: 101
22 Jun 2013, 08:02
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fozzzy
I think the answer choice should be 40 * 3^11. Please do check the source and correct me if I am wrong! Also, the fact that we are calculating the difference of the 13th and the 11th term since this is an increasing GP!
The first term or the a0 = 5 and a1 = 15. For geometric progression, a1 = r * a0 where r is the common term.
Hence, r comes out to be 3.
\(a13 - a11 = a0 * (r^13 - r^11) = 5 * (3^13 - 3^11) = 5 * 3^11 * (9-1) = 40 * 3^11\)
Hence, 40 * 3^11 should be the answer.
Regards,
Arpan
General Discussion
22 Jun 2013, 08:07
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The formula for GP is \(A1*[r ^{(n-1)}]\)
so for 11th term it will be 10 and for 13th term it will be 12
sequences-progressions-101891.html
so for 11th term it will be 10 and for 13th term it will be 12
sequences-progressions-101891.html
*precisely the difference between choice [B] and [D]*
