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jlgdr
fameatop
Asifpirlo
If a, b, and c are consecutive positive odd integers, not necessarily in that order, which of the following
must be true?
I. a + b > c
II. bc > a
III. (a + c)^2 > b

A. I only
B. II only
C. III only
D. I and II only
E. I and III only

Lets suppose that a,b,c can take any one of following three value 1,3,5. Most important point is that the options MUST BE TRUE under any condition.
I) a+b>c
Not necessarily true as 1+3<5

II) bc>a
Not necessarily true as 1.3<5

III) We don't need to check option as all the options except C can be discarded.
Thus Answer C

I didn't quite get statement 2. We are told that 1,3,5 consecutive odd integers.

Therefore, 3*5=15>1 is always true. What's missing?

Thanks!
Cheers
J :)

II says bc > a. Now, if a = 5, b = 1 and c = 3, then bc < a. Hence this option is not necessarily true.
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Asifpirlo
If a, b, and c are consecutive positive odd integers, not necessarily in that order, which of the following must be true?

I. a + b > c

II. bc > a

III. (a + c)^2 > b

A. I only
B. II only
C. III only
D. I and II only
E. I and III only

Can someone explain what the highlighted part means?
What are the possibilities that one would need to consider?
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shaderon
Asifpirlo
If a, b, and c are consecutive positive odd integers, not necessarily in that order, which of the following must be true?

I. a + b > c

II. bc > a

III. (a + c)^2 > b

A. I only
B. II only
C. III only
D. I and II only
E. I and III only

Can someone explain what the highlighted part means?
What are the possibilities that one would need to consider?

Hi Shaderon,
The same order would mean that
a < b < c or
being precise : b = a + 2
c = b + 2 = a + 4, where a is a positive odd integer

However as they are not consecutive in the same order so, above inequality a<b<c does not hold true.
i.e., any case is possible : a < b < c or a < c < b or b < a < c or b < c < a or c < a < b or c < b < a

Now,definitely we should consider the boundary case values to find how the inequality behaves.
Boundary case : taking odd numbers 1,3,5

I. a + b > c
put a =1,b=3,c=5 ;does not work

II. bc > a
put b=1,c=3,a=5 ;does not work

III. (a + c)^2 > b
put a=1,c=3,b=5 ; will work

We can reject inequalities I and II.
It is pretty clear, only inequality III is only left which holds true as shown above.
Looking at the answer options, correct option is

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Oh cause it says not necessarily in that order. Missed that part, thanks!

Cheers
J
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