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If 3 Machines can do the work in 36 hr then 4 Machines can do the work in 3/4*36 = 27 Hrs. hence time saved will be 9hr

option B is the correct answer
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3 Machines 36 hr
1 Machines 108 hrs
4 machines 27 hrs

Now 36-27=9 hrs fewer......B

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3 -> 36
4 -> x
Because they are inversely related, 4x = 3*36 => x = 27.
36-9 = 27.
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48

\(\frac{36}{3}=\) 12 hours (each machine take 12 hours)
(3 machines * 12 hours) = (4 machines take x hours)
12 * 3 = 4 * X
36 = 4x
9 = x
4 machines will take 9 hours less to finish the same order
Answer B
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a usual approach for work rate problems

3 machines, same productivity rate do some work in 36 hours, so mount of work is 108
if 1 more machine with the same rate is added then:

108 = 4*x
x = 27
Question asks "how many fewer hours" so we subtract 27 from initial 36 = 9
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Attachment:
Screen Shot 2018-10-18 at 12.23.32 AM.png
Screen Shot 2018-10-18 at 12.23.32 AM.png [ 38.2 KiB | Viewed 67665 times ]
If time taken by 4 machines is 27 hrs
Time taken by 3 machines is 36 hrs.
Question asks: how many fewer hours of simultaneous operation could the production order be fulfilled?
36-27 = 9 hrs
Same work would take 9 fewer hours.
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48


since the amount of work completed is the same, weather it will be 4 or 6 machines, I made following equation

total machines/ hours \(36*3 = 108\)


\((36-x)*4= 108\)

\(144-4x=108\)

\(4x =36\)

\(x = 9\)

So 9 hours fewer :)
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48
\(? = \left( {{\rm{time}}\,\,3\,\,{\rm{mach}}{\rm{.}}\,\,{\rm{together}}} \right) - \left( {{\rm{time}}\,\,4\,\,{\rm{mach}}{\rm{.}}\,\,{\rm{together}}} \right)\,\, = \,\,36\,\, - \,\,{?_{{\rm{temp}}}}\,\,\,\,\,\,\left[ {\rm{h}} \right]\)

\({\rm{each}}\,\,{\rm{mach}}{\rm{.}}\,\,{\rm{alone}}\,\,\, \to \,\,\,3 \cdot 36\,\,{\rm{h}}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,{?_{{\rm{temp}}}}\,\, = \,\,\,{{3 \cdot 36} \over 4}\,\,{\rm{h}}\,\,{\rm{ = }}\,\,27\,{\rm{h}}\)

\(? = 36 - 27 = \,\,9\,\,\,\left[ {\rm{h}} \right]\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48

3 machines can do a work in 36 hours.
1 machine can do a work in 36*3 = 108 hours.
4 machines can do a work in 108/4 = 27 hours.

So number of fewer hours taken when 4 machines works simultaneously = 36 - 27 = 9 hours.

Answer B
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48
The easiest way to solve this is to simply pick an easy number for the size of the production order, which is not given and hence doesn't matter (in other words, the correct answer is the same regardless of the order size), and to then calculate the number of hours required in each scenario. Let's say it takes 36 hours to make 36 golf clubs, for example. 36/36 = 1 so we make 1 golf club per hour. However, there are 3 machines so we make 1/3 of a club per hour, per machine.

So, each machine makes 1 golf club every 3 hours, and we add an additional machine. Now we have 4 machines making 1/3 + 1/3 + 1/3 + 1/3 = 4/3 clubs per hour. w = rt, so w/r= t. Since we need to make 36 golf clubs, it will take us [ [(36)/(4/3)] = 27 hours with 4 machines. 36-27 = 9, so the answer is Choice B.

Another trick is to realize that 4 is 33.3% greater than 3, so if you divide 36 by 1.33 you get 27. Be careful not to reduce 36 by 33%, though, because that will give you a false answer (Choice C).
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48

Use unitary method...

Take total work = 1
3 machines take 36 hours to complete the entire work = 1
1 machine take 36 hours to complete = 1/3 work
1 machine take 1 hour to complete = 1/ 3 * 36
4 machines take 1 hour to complete = 4/3 *36

4 machines complete the work in = 3 * 36 / 4 = 27 hours

4 machines take (36 - 27)= 9 hours less to complete the work.

Please give me KUDO s if you liked my explanation.
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kiseki
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be fulfilled?

A. 6
B. 9
C. 12
D. 27
E. 48

If 3 machines working together take 36 hours to complete a job, then 1 machine by itself will take 3 times as long, or 3 x 36 = 108 hours to complete the same job. However, 4 machines working together will take ¼ as long, or ¼ x 108 = 27 hours to complete the job. Therefore, 1 additional machine (added to 3 machines) will save 36 - 27 = 9 hours.

Answer: B
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There are multiple approaches to solve this Question. Let’s try a simple approach.
Since it is given that each machine work at the same constant rate, we can assume that each machine will do 1 order in 1 hour.
No of orders done by 1 machine in 36 hours = 36 orders
Total no of orders done by 3 machines in 36 hours = 36* 3 orders
If we add one more machine, then there is a total of 4 machines
Time taken by 4 machines to do the same no of orders = 36*3/4 = 9* 3 = 27 hours.

So four machines working together can fulfill the orders in 9 hours less time.

Option B is the answer.

Thanks,
Clifin J Francis
GMAT SME
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