mshrek
Bunuel
arunraj
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the number of ways of seating if both of them will sit next to only one other student from the group?
A. 3! x 2!
B. 4! x 2!
C. 4!
D. 3!
The question basically asks about the # of ways that Bob and Lisa sit at the ends (only this way is valid so that both of them will sit next to only one other student).
Desired arrangement is either
BXYZ
L or
LXYZ
B. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.
Answer: A.
Since there are two ends i think the answer should be 3! x 2! x 2 = 24 = 4 !
__ __ __ bob lisa , __ __ __ lisa bob = total ways = 3! x 2
bob lisa __ __ __ , lisa bob __ __ __ = total ways = 3! x 2
therefore total ways = 3! x 2 ! x 2 = 24 . Please have a relook at the OA
I am considering that both bob and lisa sit together , is my assumption wrong here ?
Your assumption is wrong.
To simplify, the question says
Lisa will sit next to only one person
Bob will sit next to only one person
__ __ __ bob lisa << bob is sitting next to 2 people lisa and some Mr. X
So if you analyze a little bit, you will realize bob and lisa can sit only on corner seats...
rest you can check Bunuel's explanation above