Last visit was: 24 Apr 2026, 07:03 It is currently 24 Apr 2026, 07:03
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
arunraj
Joined: 01 Jul 2013
Last visit: 08 Nov 2013
Posts: 1
Own Kudos:
13
 [8]
Location: United States
Concentration: General Management, Strategy
GPA: 4
WE:Business Development (Computer Software)
Posts: 1
Kudos: 13
 [8]
3
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,813
Own Kudos:
810,998
 [6]
Given Kudos: 105,871
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,813
Kudos: 810,998
 [6]
2
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
General Discussion
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,813
Own Kudos:
Given Kudos: 105,871
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,813
Kudos: 810,998
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
mshrek
Joined: 12 Nov 2012
Last visit: 04 Dec 2017
Posts: 154
Own Kudos:
Given Kudos: 126
Location: India
Concentration: Finance, Technology
Schools: ISB '18 (A)
GPA: 2.7
WE:Analyst (Computer Software)
Schools: ISB '18 (A)
Posts: 154
Kudos: 138
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
arunraj
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the number of ways of seating if both of them will sit next to only one other student from the group?

A. 3! x 2!
B. 4! x 2!
C. 4!
D. 3!

The question basically asks about the # of ways that Bob and Lisa sit at the ends (only this way is valid so that both of them will sit next to only one other student).

Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.

Answer: A.


Since there are two ends i think the answer should be 3! x 2! x 2 = 24 = 4 !

__ __ __ bob lisa , __ __ __ lisa bob = total ways = 3! x 2
bob lisa __ __ __ , lisa bob __ __ __ = total ways = 3! x 2

therefore total ways = 3! x 2 ! x 2 = 24 . Please have a relook at the OA

I am considering that both bob and lisa sit together , is my assumption wrong here ?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,813
Own Kudos:
810,998
 [1]
Given Kudos: 105,871
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,813
Kudos: 810,998
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mshrek
Bunuel
arunraj
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the number of ways of seating if both of them will sit next to only one other student from the group?

A. 3! x 2!
B. 4! x 2!
C. 4!
D. 3!

The question basically asks about the # of ways that Bob and Lisa sit at the ends (only this way is valid so that both of them will sit next to only one other student).

Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.

Answer: A.


Since there are two ends i think the answer should be 3! x 2! x 2 = 24 = 4 !

__ __ __ bob lisa , __ __ __ lisa bob = total ways = 3! x 2
bob lisa __ __ __ , lisa bob __ __ __ = total ways = 3! x 2

therefore total ways = 3! x 2 ! x 2 = 24 . Please have a relook at the OA

I am considering that both bob and lisa sit together , is my assumption wrong here ?

Your cases dons't satisfy the requirement that both of them will sit next to only one other student. For example, in XYZ{Bob}{Lisa}, Bob is next to both Z and Lisa.
User avatar
b2bt
Joined: 25 Sep 2012
Last visit: 14 Apr 2024
Posts: 192
Own Kudos:
Given Kudos: 242
Location: India
Concentration: Strategy, Marketing
GMAT 1: 660 Q49 V31
GMAT 2: 680 Q48 V34
Products:
GMAT 2: 680 Q48 V34
Posts: 192
Kudos: 651
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mshrek
Bunuel
arunraj
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the number of ways of seating if both of them will sit next to only one other student from the group?

A. 3! x 2!
B. 4! x 2!
C. 4!
D. 3!

The question basically asks about the # of ways that Bob and Lisa sit at the ends (only this way is valid so that both of them will sit next to only one other student).

Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.

Answer: A.


Since there are two ends i think the answer should be 3! x 2! x 2 = 24 = 4 !

__ __ __ bob lisa , __ __ __ lisa bob = total ways = 3! x 2
bob lisa __ __ __ , lisa bob __ __ __ = total ways = 3! x 2

therefore total ways = 3! x 2 ! x 2 = 24 . Please have a relook at the OA

I am considering that both bob and lisa sit together , is my assumption wrong here ?
Your assumption is wrong.
To simplify, the question says
Lisa will sit next to only one person
Bob will sit next to only one person

__ __ __ bob lisa << bob is sitting next to 2 people lisa and some Mr. X

So if you analyze a little bit, you will realize bob and lisa can sit only on corner seats...
rest you can check Bunuel's explanation above
User avatar
cledgard
Joined: 05 Nov 2012
Last visit: 11 Mar 2026
Posts: 163
Own Kudos:
Given Kudos: 72
Status:GMAT Coach
Location: Peru
GPA: 3.98
Expert
Expert reply
Posts: 163
Kudos: 369
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is an ambiguous question. Does the word other refer to any other student, or to another student except for Lisa and Bob?
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,047
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi cledgard,

The prompt tells us that the students will sit in 5 seats in a row next to one another. This means that each of the students will either sit next to just one of the other students (if seated in an "end" seat) or next to two of the other students (if seated in one of the three "middle" seats).

For Bob and Lisa to BOTH sit next to JUST ONE of the other students, then Bob and Lisa have to sit on the two "ends" of the row. In this way, Bob and Lisa CAN'T sit next to one another, so there's no ambiguity.

GMAT assassins aren't born, they're made,
Rich
User avatar
sutharpralhad
Joined: 07 Mar 2020
Last visit: 30 Mar 2026
Posts: 9
Own Kudos:
Given Kudos: 34
Location: India
Concentration: Strategy, Entrepreneurship
GMAT Focus 1: 605 Q84 V79 DI77
GMAT Focus 2: 635 Q83 V82 DI79
GMAT Focus 3: 655 Q85 V80 DI82
GPA: 7.77
WE:Project Management (Energy)
GMAT Focus 3: 655 Q85 V80 DI82
Posts: 9
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

arunraj
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the number of ways of seating if both of them will sit next to only one other student from the group?

A. 3! x 2!
B. 4! x 2!
C. 4!
D. 3!
The question basically asks about the # of ways that Bob and Lisa sit at the ends (only this way is valid so that both of them will sit next to only one other student).

Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.

Answer: A.
­
Hi Bunuel , 

Kindly explain why Bob and lisa can sit  at ends only . This Case XBYLZ will also meet the requirement of question that B&L will sit next to only one other student . I interpreted it as that they will not sit together . 

Thanks  
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,813
Own Kudos:
810,998
 [1]
Given Kudos: 105,871
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,813
Kudos: 810,998
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
sutharpralhad

Bunuel

arunraj
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the number of ways of seating if both of them will sit next to only one other student from the group?

A. 3! x 2!
B. 4! x 2!
C. 4!
D. 3!
The question basically asks about the # of ways that Bob and Lisa sit at the ends (only this way is valid so that both of them will sit next to only one other student).

Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.

Answer: A.
­
Hi Bunuel , 

Kindly explain why Bob and lisa can sit  at ends only . This Case XBYLZ will also meet the requirement of question that B&L will sit next to only one other student . I interpreted it as that they will not sit together . 

Thanks  
 The phrase "both of them will sit next to only one other student from the group" means Bob and Lisa each should have only one neighboring student, not two. In the XBYLZ arrangement, both Bob and Lisa are sitting next to two students each, not just one. The problem requires each to be next to only one student, which can only happen if they are at the ends.­
Moderators:
Math Expert
109813 posts
Tuck School Moderator
853 posts