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I do not understand the approach of 5C4 .

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Total Boys: 5

Total Girls: 6

Committee of 4 people with the condition of at least 3 boys: (3 boys and 1 girl) OR (4 boys and NO girl)

=> \(^{5}\mathrm{C_3}\) * \(^{6}\mathrm{C_1}\) + \(^{5}\mathrm{C_4}\)

=> 10 * 6 + 5

=> 65

Answer C
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madhavsrinivas
In how many ways can a committee of 4 people comprising at least 3 boys be formed using a group of 5 boys and 6 girls?

A) 67
B) 64
C) 65
D) 66
E) None of these

total ways to form 4 people committee with atleast 3 boys
5c3*6c1+5c4 = 65
option C
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