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Sub 505 (Easy)|   Fractions and Ratios|   Word Problems|                     
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SOLUTION

After 4,000 gallons of water were added to a large water tank that was already filled to 3/4 of its capacity, the tank was then at 4/5 of its capacity. How many gallons of water does the tank hold when filled to capacity?

(A) 5,000
(B) 6,200
(C) 20,000
(D) 40,000
(E) 80,000

4,000 gallons of water comprise 4/5 - 3/4 = 1/20, which makes the capacity of the tank equal to 4,000*20 = 80,000 gallons.

Answer: E.
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1/20x=4000..x=80000..
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x=tank capacity

4000/x = (4/5-3/4)/1
4000 = 1/20(x)
x=80000

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Let us assume the total capacity of tank to be x.

Since the tank was already filled to 3/4th(or 75%) of its capacity and 4,000 gallons of water were added to bring it to 4/5 th(or 80%) of its capacity, we can make the following inference:
5% of capacity(80%-75%) = 4000;
(5/100) * x = 4,000
x = 80,000;

Ans is (E).
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SOLUTION

After 4,000 gallons of water were added to a large water tank that was already filled to 3/4 of its capacity, the tank was then at 4/5 of its capacity. How many gallons of water does the tank hold when filled to capacity?

(A) 5,000
(B) 6,200
(C) 20,000
(D) 40,000
(E) 80,000

4,000 gallons of water comprise 4/5 - 3/4 = 1/20, which makes the capacity of the tank equal to 4,000*20 = 80,000 gallons.

Answer: E.
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After 4,000 gallons of water were added to a large water tank that was already filled to 3/4 of its capacity, the tank was then at 4/5 of its capacity. How many gallons of water does the tank hold when filled to capacity?

(A) 5,000
(B) 6,200
(C) 20,000
(D) 40,000
(E) 80,000


\(\frac{3}{4}\) of Tank = 75% of Tank

\(\frac{4}{5}\) of Tank = 80% of Tank

Given that, difference between 80% and 75% of Tank is 4000 gallons
Or, 5% of Tank = 4000 gallons

Or, Full capacity of Tank \(= 20 * 4000 = 80000\) gallons of water

Answer: (E)
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Let full capacity of tank = x

3/4th of full capacity \(= \frac{3x}{4}\)

Addition of 4000 gallons \(= \frac{3x}{4} + 4000\)

Given that addition of water takes the level to 4/5th

\(\frac{3x}{4} + 4000 = \frac{4x}{5}\)

x = 4000 * 20

= 80000
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Let x be the capacity of tank

(4/5 - 3/4) x = 4000
(0.8-0.75)x = 4000
0.05 x = 4000
x = 4000 * 20 = 80,000
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Nice Question
Here making an algebraic equation => [3/4] X +4000 = [4/5]X => X=80000
Smash E
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3/4*x+4000=4/5*x
Solving for x, and getting x = 80K
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Let the currently existing water be x
Total capacity be y

\(\frac{x}{y} = \frac{3}{4}\)

\(\frac{x+4000}{y} = \frac{4}{5}\)

\(\frac{x}{y} + \frac{4000}{y} = \frac{4}{5}\)

\(\frac{3}{4} + \frac{4000}{y} = \frac{4}{5}\)

\(\frac{4000}{y} = \frac{1}{20}\)

y = 80,000

Answer choice E
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Tank is filled to 3/4 capacity, so 1/4 is empty.
After adding 4000, Tank is filled to 4/5 capacity.
So T/4 > 4000 (Tank is still not filled to full capacity even after adding 4000)
T>16,000
we can reject atleast A, B using this logic
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\(\frac{3}{4}\) \(x\) + 4000 = \(\frac{4}{5}\) \(x\)

\(\frac{4}{5}\) \(x\) - \(\frac{3}{4}\) \(x\) = 4000

\(\frac{1}{ 20}\) * \(x\) = 4000

\(x\) = \(4000 * 20\) = \(80,000\)
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Bunuel
After 4,000 gallons of water were added to a large water tank that was already filled to 3/4 of its capacity, the tank was then at 4/5 of its capacity. How many gallons of water does the tank hold when filled to capacity?

(A) 5,000
(B) 6,200
(C) 20,000
(D) 40,000
(E) 80,000





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

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