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Updated on: 02 Apr 2014, 06:33
Originally posted by goodyear2013 on 05 Feb 2014, 12:58.
Last edited by Bunuel on 02 Apr 2014, 06:33, edited 2 times in total.
Last edited by Bunuel on 02 Apr 2014, 06:33, edited 2 times in total.
Edited the question.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
69% (02:25) correct
31%
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wrong
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A student's score on the final test in a certain course was 60% greater than the average (arithmetic mean) score of the 2 other tests the student took in the course. The student's score on the final test was what percent of the student's average test score for the entire course?
A. \(33\frac{1}{3}%\)
B. 40%
C. 75%
D. \(133\frac{1}{3}%\)
E. 160%
A. \(33\frac{1}{3}%\)
B. 40%
C. 75%
D. \(133\frac{1}{3}%\)
E. 160%
06 Mar 2014, 01:07
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Say Test1 = 100
Test2 = 100
Avg of Test1 & Test2 = 100
Final test is 60% more than above average = 160
Avg of all 3 tests combined \(= \frac{360}{2} = 120\)
% increase = \(\frac{160}{120}* 100 = 133 \frac{1}{3}\)
Answer = D
Test2 = 100
Avg of Test1 & Test2 = 100
Final test is 60% more than above average = 160
Avg of all 3 tests combined \(= \frac{360}{2} = 120\)
% increase = \(\frac{160}{120}* 100 = 133 \frac{1}{3}\)
Answer = D
General Discussion
05 Feb 2014, 17:55
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Given :
Let scores be s1,s2,s3
\(s3 = 1,6 (\frac{s1}{2}+ \frac{s2}{2})\)
(1) rearranging this :
\(s1+s2 = \frac{5}{4}*s3\)
(2) Average of 3 score is =
\(\frac{1}{3}*(s1+s2+s3)\)
We can use the information at (1) to replace \(s1+s2\) into equation (2)
\(Average =\frac{1}{3} * ( \frac{5}{4}*s3 +s3)\)
\(Average = \frac{1}{3} * ( \frac{9}{4}*s3)\)
\(Average = \frac{3}{4}*s3\)
\(s3 = \frac{4}{3}*Average\)
\(s3 = 1.33333 * Average\)
making s3 133% of the Average
Answer D
Let scores be s1,s2,s3
\(s3 = 1,6 (\frac{s1}{2}+ \frac{s2}{2})\)
(1) rearranging this :
\(s1+s2 = \frac{5}{4}*s3\)
(2) Average of 3 score is =
\(\frac{1}{3}*(s1+s2+s3)\)
We can use the information at (1) to replace \(s1+s2\) into equation (2)
\(Average =\frac{1}{3} * ( \frac{5}{4}*s3 +s3)\)
\(Average = \frac{1}{3} * ( \frac{9}{4}*s3)\)
\(Average = \frac{3}{4}*s3\)
\(s3 = \frac{4}{3}*Average\)
\(s3 = 1.33333 * Average\)
making s3 133% of the Average
Answer D
