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21 Oct 2014, 21:05
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
67% (01:12) correct
33%
(01:25)
wrong
based on 323
sessions
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What is the total number of integers between 101 and 202 that are divisible by 3?
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
22 Oct 2014, 00:28
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PareshGmat
\(# \ of \ multiples \ of \ x \ in \ the \ range = \frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1\)
(201 - 102)/3 + 1 = 34.
Answer: D.
General Discussion
21 Oct 2014, 22:57
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PareshGmat
First no divisible by 3: 102
Last no divisible by 3: 201
Note that any number is divisible by 3 if the sum of the digits is divisible by 3
So total numbers divisible by 3:
202=102+(n-1)*3 where n is total numbers
3n=102, n=34
