PareshGmat wrote:
What is the total number of integers between 101 and 202 that are divisible by 3?
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
First no divisible by 3: 102
Last no divisible by 3: 201
Note that any number is divisible by 3 if the sum of the digits is divisible by 3
So total numbers divisible by 3:
202=102+(n-1)*3 where n is total numbers
3n=102, n=34
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69% (01:16) correct 
