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Bunuel
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First integer divisible by 3 in this range = 102 = 3*34
Last integer divisible by 3 in this range = 201 = 3*67

So the list is like this:
3*34, 3*35, 3*36, ......, 3*67

So basically we have to calculate the number of consecutive integers from 34 to 67
67-34 +1 = 34

Hence answer is D
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102-201=99

number of integers divisible by 3 is 99/3 +1 = 34.

u can get it in 35 seconds
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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