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21 Oct 2014, 21:05
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D
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Difficulty:
35%
(medium)
Question Stats:
67% (01:13) correct
33%
(01:23)
wrong
based on 294
sessions
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What is the total number of integers between 101 and 202 that are divisible by 3?
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
22 Oct 2014, 00:28
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PareshGmat
What is the total number of integers between 101 and 202 that are divisible by 3?
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
\(# \ of \ multiples \ of \ x \ in \ the \ range = \frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1\)
(201 - 102)/3 + 1 = 34.
Answer: D.
General Discussion
21 Oct 2014, 22:57
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PareshGmat
What is the total number of integers between 101 and 202 that are divisible by 3?
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
(A) 31
(B) 32
(C) 33
(D) 34
(E) 35
First no divisible by 3: 102
Last no divisible by 3: 201
Note that any number is divisible by 3 if the sum of the digits is divisible by 3
So total numbers divisible by 3:
202=102+(n-1)*3 where n is total numbers
3n=102, n=34
