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arshu27
using pythogoras theoram for the top smaller triangle i got the value of y=a+k. is there something wrong in my understanding?

Please show your work.
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arshu27
using pythogoras theoram for the top smaller triangle i got the value of y=a+k. is there something wrong in my understanding?


There is no need to use Pythagoras theorem in this question for solution.

Refer diagram below for calculation

Attachment:
triangle.png
triangle.png [ 4.17 KiB | Viewed 6217 times ]

Answer = B) x = bk/a; y = a-k;
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Consider triangle ABC,
Using the distance formula we can find out AC which is sqrt(x^2+(y-a)^2).

using pythogoras theoram,

AC^2=BC^2 + AB^2.

therefore,

x^2+(y-a)^2=k^2 +x^2

Cancelling x^2 we get,

(y-a)^2=k^2

so k=y-a

y=k+a.

can you tell me what am i missing.Bunuel
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arshu27
using pythogoras theoram for the top smaller triangle i got the value of y=a+k. is there something wrong in my understanding?


Co-ordinate geometry is best done with a hand made diagram.

Make the diagram of this question and label every point where any two lines intersect. What are the co-ordinates of the point opposite the hypotenuse of the smaller top triangle? The co-ordinates are (0, y). Why? Because the co-ordinates of the point in line with this one are (x, y). Since this line runs parallel to the x axis, the y co-ordinate will remain the same i.e. y.

From there, you directly get that y = a - k.
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The question literally had two different solutions. Pythagorean theorem gives y=k+a and x=-bk/a.
The other solution gives signs opposite to the solutions we get using Pythagorean theorem. Unless there's a reason why Pythagorean theorem cannot be used, not sure why we it's wrong.

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Anulitha
The question literally had two different solutions. Pythagorean theorem gives y=k+a and x=-bk/a.
The other solution gives signs opposite to the solutions we get using Pythagorean theorem. Unless there's a reason why Pythagorean theorem cannot be used, not sure why we it's wrong.

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Because

(y-a)^2=k^2

so k=y-a

is wrong in the pythagorean solution given above.

When you square root, you get

|y - a| = |k|
Now we know that a is greater than y (since it is higher up on the y axis). So (y - a) is negative.
So |y - a| = -(y - a) = a - y

Since k represents the distance, |k| = k

So a - y = k

y = a - k
Only correct answer.
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