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Bunuel
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Ratio = (2π * 3) / (2π * 1) = 3:1
Answer C
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Bunuel

Tough and Tricky questions: Geometry.




The figure above shows three circles, all centered on point O. What is the ratio of the circumference of the outermost circle to that of the innermost circle?

A. √3 : 1
B. 2 : 1
C. 3 : 1
D. π : 1
E. 9 : 1

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Attachment:
2014-12-30_1849.png


Circumference of outer most circle = 2* π * 3 = 6π
Inner circle = 2 * π * 1 = 2π

6π:2π
3:1
Ans C
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Answer is C
circumference of outer circle: 2*pi *3
circumference of inner circle: 2*pi*1

Ratio of outer to inner=2*pi*3/2*pi*1=3/1
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Bunuel

Tough and Tricky questions: Geometry.




The figure above shows three circles, all centered on point O. What is the ratio of the circumference of the outermost circle to that of the innermost circle?

A. √3 : 1
B. 2 : 1
C. 3 : 1
D. π : 1
E. 9 : 1

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Attachment:
2014-12-30_1849.png

OFFICIAL SOLUTION:

The radius of the outermost circle is 1 + 1 + 1 = 3 and the radius of the innermost circle is 1.

We can now determine the circumferences of the outermost and innermost circles using the following formula:
C = 2πr.

Circumference of Outermost Circle:
C = 2π(3) = 6π.

Circumference of Innermost Circle:
C = 2π(1) = 2π.

The ratio asked for in the question can be found by dividing the circumference of the outermost circle by that of the innermost:
6π/2π = 3/1.

The correct answer is choice (C).
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