Two trains are traveling on parallel tracks in the same direction. The

Question

Tough and Tricky questions: Distance/Rate Problems.

Two trains are traveling on parallel tracks in the same direction. The faster train travels at 130 miles per hour, while the slower train travels at 100 miles per hour. At 2 o’clock the faster train is 10 miles behind the slower one. How far apart are the two trains at 5 o'clock?

A. 60 miles
B. 80 miles
C. 90 miles
D. 120 miles
E. 400 miles

Kudos for a correct solution.

A. 60 miles
B. 80 miles
C. 90 miles
D. 120 miles
E. 400 miles

PareshGmat · Accepted Answer

Answer = B. 80 miles

Relational speed = 130 - 100 = 30 miles per hour

In 3 hours, difference = 30 * 3 = 90 miles

Fast train trailing 10 miles, so effective difference = 90 - 10 = 80 miles

littlewarthog · Answer

Answer B.

The relative speed of the two trains is 30 miles per hour. If the faster train is 10 miles behind the slower one at 2 o'clock, it must be 90 miles further 3 hours later. That means, it is 80 miles ahead of the slower train at 5 o'clock.

g106 · Answer

In three hours faster train travels 390 miles
In three hours slower train travels 300 miles

since the faster train was 10 miles behind at the starting the distance between the trains at 5 o clock is 390-300-10 = 80

Ans B

DesiGmat · Answer

Relative Speed = 30
Distance Travel in 3 hours = 30*3 = 90
Already in-between distance = 10 miles

So the answer has to be 90-10 = 80miles
Option B

Bunuel · Answer

OFFICIAL SOLUTION:

(B) The faster train is traveling 30 mph faster than the slower train. At 5 o'clock the faster train will travel 3 hours × 30 mph = 90 miles more than the slower one. Considering that it is 10 miles behind the slower train at 2 o’clock, it will be 90 – 10 = 80 miles ahead at 5 o’clock.

The correct answer is B.

Arsh4MBA · Answer

Relative speed is 30 miles per hr.

So at 2 o'clock Train F is 10 miles behind.
So in 3hrs it has to be 90 miles ahead consider relative speed of 30mph.
So at 5 it will be -10+90 = 80 miles ahead

ScottTargetTestPrep · Answer

In 3 hours, the faster train has traveled 130 x 3 = 390 miles and the slower train has traveled 100 x 3 = 300 miles. Thus, after 3 hours, the faster train should be 90 miles ahead of the slower train. However, since at 2 o’clock the faster train is 10 miles behind the slower one, the faster train is only 90 - 10 = 80 miles ahead of the slower train.

Answer: B

rgreenhill · Answer

Imagine the slower train is stationary and then the faster train is moving away from it at 30mph. Between 2 and 5 the faster train would have travelled 3*30 miles = 90 miles. If it starts from 10 miles behind, then it is 80 miles in front.

rgreenhill · Answer

Imagine the slower train is stationary and then the faster train is moving away from it at 30mph. Between 2 and 5 the faster train would have travelled 3*30 miles = 90 miles. If it starts from 10 miles behind, then it is 80 miles in front.

bumpbot · Answer

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