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20 Jan 2015, 11:46
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
69% (01:11) correct
31%
(01:19)
wrong
based on 449
sessions
History
Date
Time
Result
Not Attempted Yet
A librarian has a set of ten books, including four different books about Abraham Lincoln. The librarian wants to put the ten books on a shelf with the four Lincoln books next to each other, somewhere on the shelf among the other six books. How many different arrangements of the ten books are possible?
(A) (10!)/(4!)
(B) (4!)(6!)
(C) (4!)(7!)
(D) (4!)(10!)
(E) (4!)(6!)(10!)
For a set of Counting Practice Problems for the GMAT, as well as the OE for this particular question, see:
https://magoosh.com/gmat/2015/counting-p ... -the-gmat/
Mike
(A) (10!)/(4!)
(B) (4!)(6!)
(C) (4!)(7!)
(D) (4!)(10!)
(E) (4!)(6!)(10!)
For a set of Counting Practice Problems for the GMAT, as well as the OE for this particular question, see:
https://magoosh.com/gmat/2015/counting-p ... -the-gmat/
Mike
24 Aug 2018, 07:23
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Bookmarks
mikemcgarry
Let's first "glue" the 4 Lincoln books together to create one SUPER BOOK (this will ensure that the 4 books remain together)
We now have 7 books: 6 regular books and 1 super book
We can arrange these 7 books in 7! ways.
KEY: For each of the 7! arrangements, we can take the 4 Lincoln books (that comprise the SUPER BOOK) and arrange them in 4! ways.
So, the TOTAL number of arrangements = (7!)(4!)
Answer: C
Cheers,
Brent
20 Jan 2015, 15:29
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mikemcgarry
Hi Mike,
You can club the four Lincoln books as one, which leaves us with six other books plus this one to think about. So, these seven items can be arranged in 7! ways, and since the four books can be moved around among themselves with each combination giving us a new overall combination, we have an additional 4! ways. Therefore, the answer would be 7!*4!, which is C.
