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05 Feb 2015, 09:20
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
85% (00:58) correct
15%
(01:39)
wrong
based on 177
sessions
History
Date
Time
Result
Not Attempted Yet
Penny, Leonard, and Sheldon each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/4, 1/8, and 1/3, respectively, what is the probability that Penny and Leonard, but not Sheldon, will make the basket?
A. 1/96
B. 1/48
C. 1/24
D. 1/12
E. 17/24
A. 1/96
B. 1/48
C. 1/24
D. 1/12
E. 17/24
05 Feb 2015, 17:29
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Sheldon may need more force: https://www.youtube.com/watch?v=4QPetCN6b6Q
P(Sheldon misses) = 1 - P(Sheldon makes) = 1 - 1/3 = 2/3
P(Penny makes AND Leonard makes AND Sheldon misses) = 1/4 * 1/8 * 2/3 = 2/96 = 1/48
The correct answer is B.
P(Sheldon misses) = 1 - P(Sheldon makes) = 1 - 1/3 = 2/3
P(Penny makes AND Leonard makes AND Sheldon misses) = 1/4 * 1/8 * 2/3 = 2/96 = 1/48
The correct answer is B.
05 Feb 2015, 18:40
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Bunuel
(Probability Penny is successful) * (Probability Leonard is successful) * (Probability Sheldon is unsuccessful) =
(1/4)*(1/8)*(2/3) = 1/48
Answer: B
My question is how come we don't multiply (1/48) by 3? Order doesn't matter in this case, so don't we have to account for the number of ways?
