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Updated on: 13 Feb 2015, 04:38
Originally posted by gmatmania17 on 13 Feb 2015, 03:40.
Last edited by Bunuel on 13 Feb 2015, 04:38, edited 1 time in total.
Last edited by Bunuel on 13 Feb 2015, 04:38, edited 1 time in total.
Edited the tags
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:10) correct
29%
(01:07)
wrong
based on 255
sessions
History
Date
Time
Result
Not Attempted Yet
A "word" is defined as a sequence of three dots arranged in a row. Each dot is colored either yellow or blue. How many distinct words can be formed?
A 3
B 5
C 6
D 8
E 9
I know it is a question on permutations but the problem is that for me it is a tricky question.
Thank you in advance
A 3
B 5
C 6
D 8
E 9
I know it is a question on permutations but the problem is that for me it is a tricky question.
Thank you in advance
13 Feb 2015, 04:32
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Bookmarks
hi,
there are two ways of possibilities..
1) all three same colour- YYY or BBB- 2 ways
2) two of one colour and one of different colour- 3!/2!-3ways..
now two /one could be Y/B or B/Y.... so 3*2=6..
total 6+2=8 ans D
there are two ways of possibilities..
1) all three same colour- YYY or BBB- 2 ways
2) two of one colour and one of different colour- 3!/2!-3ways..
now two /one could be Y/B or B/Y.... so 3*2=6..
total 6+2=8 ans D
13 Feb 2015, 04:40
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gmatmania17
***
Each dot can be either yellow or blue, so 2 options for each dot: 2*2*2 = 8.
Answer: D.
Hope it's clear.
