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Answer = C. 44 mph

Average speed \(= \frac{Total distance}{Total time} = \frac{40+180}{\frac{40}{20} + \frac{180}{60}} = \frac{220}{5} = 44\)
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Bunuel
A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip?

A. 36 mph
B. 40 mph
C. 44 mph
D. 52 mph
E. 58 mph

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MAGOOSH OFFICIAL SOLUTION:

In phase #1 of the trip, the car traveled 40 mi at 20 mph. That time of this phase was:
time = distance/rate = (40 mi)/(20 mph) = 2 hr

In phase #2 of the trip, the car traveled 180 mi at 60 mph. That time of this phase was:
time = distance/rate = (180 mi)/(60 mph) = 3 hr

The total distance of the trip = 40 mi + 180 mi = 220 mi
The total time of the trip = 2 hr + 3 hr = 5 hr
The average speed of trip is given by
speed = distance/time = (220 mi)/(5 hr) = 44 mph

Answer: C.
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Average Speed = (Total Distance traveled) / (Total Time taken)

Total Distance = 40 +180 = 220 miles
Total Time = (40/20) +(180/60) = 2 + 3 = 5 hours

Average Speed = 220 /5 = 44 mph
Correct Option : C
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Average time = Total distance/Total time taken.

Average time = 220/5 = 44

C is the answer

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Bunuel
A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip?

A. 36 mph
B. 40 mph
C. 44 mph
D. 52 mph
E. 58 mph

Kudos for a correct solution.

Time taken for first \(40\) miles is \frac{40}{20} = \(2\) Hours
Time taken for next \(180\) miles is \frac{180}{50} = \(3\) Hours

So, For travelling 220 miles time taken is 5 Hours.

So, Avg Speed is \(\frac{220}{5} = 44 \ mph\), Answer must be (C)
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