A bookseller has two display windows. She plans to display 4 new fict

Question

A bookseller has two display windows. She plans to display 4 new fiction books in the left window, and 3 new non-fiction books in the right window. Assuming she can put the four fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?

A. 24
B. 72
C. 144
D. 336
E. 420

Kudos for a correct solution.

A. 24 
B. 72 
C. 144 
D. 336 
E. 420

Kudos for a correct  solution .

chetan2u · Answer

4 on left can be arranged in 4!.. and 3 on right in 3!..
total=4!*3!=144
ans C

ynaikavde · Answer

Two displays books could be arranged n! # of total arrangements are combinations multiplied together,
3!*4! =6*24=144
Answer is C

LaxAvenger · Answer

Answer is combination of left window:

4! = 4 * 3 * 2

AND (means multiply)

3! = 3*2

together 4 * 3 * 2 * 3 * 2 = 144

Answer C

OptimusPrepJanielle · Answer

Left hand side books can be ordered in 4! ways = 24 ways Right hand side books can be ordered in 3! ways = 6 ways Total number of ways = 24 * 6 = 144 Hence option C. -- Optimus Prep's GMAT On Demand course for only $299 covers all verbal and quant. concepts in detail. Visit the following link to get your 7 days free trial account: https://www.optimus-prep.com/gmat-on-demand-course

Bunuel · Answer

MAGOOSH OFFICIAL SOLUTION:

The left window will have permutations of the 4 fiction books, so the number of possibilities for that window is
permutations = 4! = (4)(3)(2)(1) = 24
 
The right window will have permutations of the 3 non-fiction books, so the number of possibilities for that window is
permutations = 3! = (3)(2)(1) = 6
 
Any of the 24 displays of the left window could be combined with any of the 6 displays of the right window, so the total number of configurations is 24*6 = 144

Answer: C.

EMPOWERgmatRichC · Answer

Hi All,

We're told that a bookseller has two display windows - and she plans to display 4 new fiction books in the left window and 3 new non-fiction books in the right window. Assuming she can put the four fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows. This is a mid-level Permutation question and requires just a bit of multiplication to solve.

To start, since we are putting the books in order (without any restrictions), we can use basic multiplication (re: factorials) to solve:

For the 4 fiction books, there are 4! = (4)(3)(2)(1) = 24 ways to arrange those books in the window 
For the 3 non-fiction books, there are 3! = (3)(2)(1) = 6 ways to arrange those books in the window 
In total, we have (24)(6) = 144 different ways to arrange the books.

Final Answer:  C

GMAT assassins aren't born, they're made, 
Rich

ScottTargetTestPrep · Answer

The number of configurations is 4! x 3! = 24 x 6 = 144.

Answer: C

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