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04 Mar 2015, 04:18
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:16) correct
25%
(02:47)
wrong
based on 390
sessions
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The median of a triangle is the line from any vertex to the midpoint of the opposite side. Triangle ABC has vertices A = (0, 5), B = (–1, –1), and C = (5, 2). What is the slope of the median from A to the midpoint of BC?
A. –3/4
B. –4/3
C. –5
D. –5/2
E. –9/4
A. –3/4
B. –4/3
C. –5
D. –5/2
E. –9/4
08 Mar 2015, 14:44
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Bunuel
For your visual understanding, here’s a diagram of the situation.
First to find the midpoint of B & C — average the x-coordinates: (–1+ 5)/2 = 2; and average the y-coordinates: (–1 + 2)/2 = 1/2. Thus, the midpoint has coordinates (2, 1/2). We want the slope from A = (0, 5) to (2, 1/2). The rise is the change in the y-coordinates: 1/2 – 5 = -9/2. The run is the change in the x-coordinates: 2 – 0 = 2. Slope = rise/run = [–9/2]/2 = –9/4.
Answer = (E)
Attachment:
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General Discussion
27 Jun 2016, 10:53
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I don't understand why can't we use the slope of AB, so 1/2 and it's negative inverse to get the perpendicular slope, so -2 ?..
