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Updated on: 09 Sep 2024, 10:51
Originally posted by janosfazekas91 on 13 Mar 2015, 03:58.
Last edited by Bunuel on 09 Sep 2024, 10:51, edited 3 times in total.
Last edited by Bunuel on 09 Sep 2024, 10:51, edited 3 times in total.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (01:42) correct
29%
(01:46)
wrong
based on 601
sessions
History
Date
Time
Result
Not Attempted Yet
If n is a prime number, which of the following could be true?
A. \(n^n=n\)
B. \(\frac{n^2}{4}\) is even
C. \((n)(n^n)\) is negative
D. \(n^2+n^3= n^5\)
E. \(\frac{n^n}{4} = 1^{(n-1)}\)
A. \(n^n=n\)
B. \(\frac{n^2}{4}\) is even
C. \((n)(n^n)\) is negative
D. \(n^2+n^3= n^5\)
E. \(\frac{n^n}{4} = 1^{(n-1)}\)
13 Mar 2015, 06:12
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if n is a prime number
1)n^n=n
2)n^2/4= is even
3)(n)(n^n) = is negative
4)n^2+n^3= n^5
5)n^n/4 = 1^(n-1)....
hi the easiest and fastest method to do is knowing that only one prime number is even and rest odd and fixing this on the choices..
1)n^n=n
no integer except 1 can fit in so out
2)n^2/4= is even
we know only 2 is even prime number and n^2/4 is one... so out
3)(n)(n^n) = is negative
all values are positive so cannot be true...
4)n^2+n^3= n^5
this is not possible as n^2*n^3= n^5
5)n^n/4 = 1^(n-1)
n as 2 straight way gives the answer....
1)n^n=n
2)n^2/4= is even
3)(n)(n^n) = is negative
4)n^2+n^3= n^5
5)n^n/4 = 1^(n-1)....
hi the easiest and fastest method to do is knowing that only one prime number is even and rest odd and fixing this on the choices..
1)n^n=n
no integer except 1 can fit in so out
2)n^2/4= is even
we know only 2 is even prime number and n^2/4 is one... so out
3)(n)(n^n) = is negative
all values are positive so cannot be true...
4)n^2+n^3= n^5
this is not possible as n^2*n^3= n^5
5)n^n/4 = 1^(n-1)
n as 2 straight way gives the answer....
General Discussion
13 Mar 2015, 04:07
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janosfazekas91
E should be the answer.
2^2/4 = 1^(2-1)
