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n=7, xhat=12.2, sum of 4 numbers = 42,8.

Total=n*xhat=85,4.
The three remaining: 85,4-42,8=42,6.

42,6/3=14,2 = B
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Sum(7)=7*12.2
Sum(4)=42.8

Hence Sum(3)=42.6

Hence Mean = 14.2

Hence B
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dkumar2012
The average (arithmetic mean) of seven numbers is 12.2
If the sum of four of these numbers is 42.8, what is the average of the other 3 numbers?
(a) 12.4
(b) 14.2
(c) 16.8
(d) 18.6
(e) 19.2

Total of 7 numbers is 12.2*7 = 85.4

Total of 4 numbers is 42.8

So, Total of 3 numbers is 85.4 - 42.8 = 42.6

Average of the 3 numbers is 42.6/3 = 14.2

Hence, answer will be (B) 14.2

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Easy way out

Total of 7 numbers = 85.4 (1)
Total of 4 numbers = 42.8 (2)
(1)-(2)
Total of 3 numbers = 42.60
Average of 3 numbers = 42.60/3 =14.20
Hence Option B
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