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yenh
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The average of 10 consecutive integers is 12. Then, 9 is deducted from 20 Aug 2015, 22:54
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71% (02:02) correct 29% (02:28) wrong based on 31 sessions

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The average of 10 consecutive integers is 12. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average.
A. 55
B. 50
C. 6
D. 7.5
E. 7

This question is not difficult. However, I am afraid that there is something wrong with the question.
As I know, in an evenly spaced set, average = median = middle terms (if the number of terms is odd) = average of the two middle terms (if the number of terms is even). In this 10 consecutive integers, the average cannot be an integer (the average of two consecutive integers cannot be another integer).
Am I wrong?

Thanks indeed.

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Bunuel
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The average of 10 consecutive integers is 12. Then, 9 is deducted from 20 Aug 2015, 23:02
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yenh
The average of 10 consecutive integers is 12. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average.
A. 55
B. 50
C. 6
D. 7.5
E. 7

This question is not difficult. However, I am afraid that there is something wrong with the question.
As I know, in an evenly spaced set, average = median = middle terms (if the number of terms is odd) = average of the two middle terms (if the number of terms is even). In this 10 consecutive integers, the average cannot be an integer (the average of two consecutive integers cannot be another integer).
Am I wrong?

Thanks indeed.
Show more

You are right. I think it should be 11 consecutive integers and numbers subtracted 10, 9, ...

In this case the answer would be (11*12-(10+9+8+7+6+5+4+3+2+1))/11 = 7.
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yenh
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The average of 10 consecutive integers is 12. Then, 9 is deducted from 21 Aug 2015, 08:48
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Bunuel
yenh
The average of 10 consecutive integers is 12. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average.
A. 55
B. 50
C. 6
D. 7.5
E. 7

This question is not difficult. However, I am afraid that there is something wrong with the question.
As I know, in an evenly spaced set, average = median = middle terms (if the number of terms is odd) = average of the two middle terms (if the number of terms is even). In this 10 consecutive integers, the average cannot be an integer (the average of two consecutive integers cannot be another integer).
Am I wrong?

Thanks indeed.

You are right. I think it should be 11 consecutive integers and numbers subtracted 10, 9, ...

In this case the answer would be (11*12-(10+9+8+7+6+5+4+3+2+1))/11 = 7.
Show more

Hi Bunuel,
I got this question from the Flash Card Set of GMAT ToolKit, please correct it. Many thanks.
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The average of 10 consecutive integers is 12. Then, 9 is deducted from 21 Aug 2015, 09:30
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10 consecutive numbers ...
lets have x , x+1, x+2 and so on till x+9 ... sum of which gives 10x +45
also in the question it is given ..
10x + 45 =120
i.e sum of these 10 terms to be 120
now 45 is subtracted from this 120 we are then left with 75 ,
though the total number of terms remain 10
The new average thus -- 75/10 =7.5

correct is it ?
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Shreeya24
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The average of 10 consecutive integers is 12. Then, 9 is deducted from 21 Aug 2015, 09:44
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Sine the set has consecutive integers, it means (F+L)/2 = 12 i.e, F+L = 24 ........(1)
"F" stands for First number
"L" stands for Last number
The second statements substracts the number in such a way that the resulted set will again consists of consecutive numbers. But now "F" will be F-9 and "L" will remain same.
Since its consecutive integer set, A (New Average) = ((F-9)+L)/2 i.e, 2A = F+L-9......(2).
Substitute F+L value from equation (1) and you will get A = 7.5
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The average of 10 consecutive integers is 12. Then, 9 is deducted from 21 Aug 2015, 11:04
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Hi All,

The only 'issue' with this question is the use of the word 'consecutive' - if you IGNORE that word, then you can proceed with the question normally. As it stands, the 10 numbers involved do NOT need to be consecutive NOR do they even need to be integers - the two facts (10 numbers and an average of 12) is enough for you to proceed with the rest of the question and get the correct answer.

GMAT assassins aren't born, they're made,
Rich

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