A certain liquid passes through a drain at a rate of w/20 gallons ever

Question

A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w(
D. w/(3xy)
E. 3y/(wx)

Skywalker18 · Accepted Answer

Time needed for w/20 gallons of liquid to pass through a drain = x seconds
Time needed for w gallons of liquid to pass through a drain = 20x seconds

Time needed for y gallons of liquid to pass through a drain = (20x/w)*y = 20xy/w seconds
 = (20xy/w )/60 = xy/(3w) mins

Answer C

CounterSniper · Answer

Can be done using unitary method.

w/20 gallons every x seconds
therefore in 1 second W/20x gallons
in 60 seconds (w/20x)*60 = 1 minute
so
3w/x gallons pass in 1 minute
1 gallon in x/3w minutes
y gallons in xy/3w minutes

HardWorkBeatsAll · Answer

w/20 gallons every x seconds => w/20x gallons per second => (60w/20x) gallons per minute (we calculate this because the final answer is required to be in minutes).

So, we have

60w/20x gallons in 1 minute

y gallons in how many minutes?

Minutes = y*1 / (60w/20x) = xy/3w

Hence, (C)

shashankism · Answer

Rate of passing of liquid = w/20 gallons every x seconds = w/(20x) gallons per second
Time taken by y gallons to pass through the drain = y/  seconds = 20xy/w seconds
in minutes = 20xy/(w*60) = xy/3w

Answer C

EgmatQuantExpert · Answer

Solution

Given:  
 • The liquid passes through the drain at the rate of  \frac{w}{20}  gallons in every x seconds

To find:  
 • In how many minutes, y gallons of liquid can pass through the drain.

Approach and Working:

In every x seconds,  \frac{w}{20}  gallons of liquid passes.
 • In x seconds =>  \frac{w}{20}  gallons pass through the drain.
• Therefore, in 1 seconds=  \frac{w}{(20x}  gallons pass through the drain.
• Therefore, in 1 minute= \frac{(w*60)}{(20*x)}  =  \frac{3w}{x}  gallons pass through the drain.

Since  \frac{3w}{x}  gallons pass through the drain in 1 minute. Then, 1 gallon will pass through the drain in:
 • 1-gallon pass through the drain =  \frac{x}{3w}  minutes

Hence,  y gallon will pass thorough the drain in  \frac{xy}{3w} minutes .

Hence, the correct answer is option C.

Answer: C

fskilnik · Answer

Excellent opportunity to use UNITS CONTROL , one of the most powerful tools of our method!

\frac{{\,\,\frac{w}{{20}}\,\,}}{x}\,\,\,\frac{{{	ext{gallons}}}}{{	ext{s}}}\,\,\, = \,\,\,\frac{w}{{20\,\,x}}\,\,\,\frac{{{	ext{gallons}}}}{{	ext{s}}}

?\,\,\,\min \,\,\, \leftrightarrow \,\,\,y\,\,\,{	ext{gallons}}\,

?\,\,\, = \,\,\,y\,\,{	ext{gallons}}\,\,\,\left( {\frac{{\,20\,\,x\,\,{	ext{s}}\,}}{{w\,\,{	ext{gallons}}}}\,\,\begin{array}{*{20}{c}}
 
earrow \ 
 
earrow 
\end{array}} ight)\,\,\,\,\,\left( {\frac{{\,1\,\,\min \,}}{{60\,\,{	ext{s}}}}\,\,\begin{array}{*{20}{c}}
 
earrow \ 
 
earrow 
\end{array}} ight)\,\,\,\, = \,\,\,\,\frac{{20\,\,xy}}{{60\,\,w}}\,\,\, = \,\,\,\frac{{xy}}{{\,3w\,}}\,\,\,\,\,\,\,\,\left

Obs.: arrows indicate  licit converters .

This solution follows the notations and rationale taught in the GMATH method.

Regards, 
Fabio.

Seryozha · Answer

In every rate question, it's appropriate to first create the equilibrium of time -- all represent in the hour, minute, second and so forth. Then try to find the rate of this particular time:
w/60 gallon in x/60 minute or 60w/20x gallon per minute. 
y:60w/20x or y:3w/x, which equals to xy/3w.

ScottTargetTestPrep · Answer

The rate is (w/20)/x = w/(20x)

So y gallons will pass through the drain in y/(w/(20x)) = 20xy/w seconds, which is (20xy/w)/60 = 20xy/(60w) = xy/(3w) minutes

Answer: C

EMPOWERgmatRichC · Answer

Hi All,

We're told that a certain liquid passes through a drain at a rate of W/20 gallons every X SECONDS. We're asked how many MINUTES it would take Y gallons to pass through the drain. This question can be solved in a number of different ways, including by TESTing VALUES.

IF.... 
W=20 and X=2, then 20/20 = 1 gallon passes through every 2 seconds 
Y = 30 gallons --> which would take 2(30) = 60 seconds = 1 minute 
so we're looking for an answer that equals 1 when W=20, X=3 and Y=30. There's only one answer that matches....

Final Answer:  C

GMAT assassins aren't born, they're made, 
Rich

rak08 · Answer

for every min --> w/20*60/x = 3w/x
so for y gallons = y/(3w/x) = yx/3w

A certain liquid passes through a drain at a rate of w/20 gallons ever

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A certain liquid passes through a drain at a rate of w/20 gallons ever

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