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A certain liquid passes through a drain at a rate of w/20 gallons ever

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A certain liquid passes through a drain at a rate of w/20 gallons ever [#permalink]

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New post 16 Nov 2015, 03:19
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Question Stats:

60% (01:18) correct 40% (01:22) wrong based on 136 sessions

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A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w(
D. w/(3xy)
E. 3y/(wx)

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A certain liquid passes through a drain at a rate of w/20 gallons ever [#permalink]

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New post Updated on: 16 Nov 2015, 04:52
1
Time needed for w/20 gallons of liquid to pass through a drain = x seconds
Time needed for w gallons of liquid to pass through a drain = 20x seconds

Time needed for y gallons of liquid to pass through a drain = (20x/w)*y = 20xy/w seconds
= (20xy/w )/60 = xy/(3w) mins

Answer C
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Originally posted by Skywalker18 on 16 Nov 2015, 03:49.
Last edited by Skywalker18 on 16 Nov 2015, 04:52, edited 2 times in total.
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Re: A certain liquid passes through a drain at a rate of w/20 gallons ever [#permalink]

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New post 16 Nov 2015, 03:59
Can be done using unitary method.

w/20 gallons every x seconds
therefore in 1 second W/20x gallons
in 60 seconds (w/20x)*60 = 1 minute
so
3w/x gallons pass in 1 minute
1 gallon in x/3w minutes
y gallons in xy/3w minutes
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Re: A certain liquid passes through a drain at a rate of w/20 gallons ever [#permalink]

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New post 16 Nov 2015, 04:00
1
w/20 gallons every x seconds => w/20x gallons per second => (60w/20x) gallons per minute (we calculate this because the final answer is required to be in minutes).

So, we have

60w/20x gallons in 1 minute

y gallons in how many minutes?


Minutes = y*1 / (60w/20x) = xy/3w

Hence, (C)

Bunuel wrote:
A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w(
D. w/(3xy)
E. 3y/(wx)

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Re: A certain liquid passes through a drain at a rate of w/20 gallons ever [#permalink]

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New post 09 Apr 2018, 21:54
Bunuel wrote:
A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w(
D. w/(3xy)
E. 3y/(wx)


Rate of passing of liquid = w/20 gallons every x seconds = w/(20x) gallons per second
Time taken by y gallons to pass through the drain = y/[w/(20x)] seconds = 20xy/w seconds
in minutes = 20xy/(w*60) = xy/3w

Answer C
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Re: A certain liquid passes through a drain at a rate of w/20 gallons ever [#permalink]

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New post 09 Apr 2018, 23:38

Solution



Given:
    • The liquid passes through the drain at the rate of \(\frac{w}{20}\) gallons in every x seconds

To find:
    • In how many minutes, y gallons of liquid can pass through the drain.

Approach and Working:

In every x seconds, \(\frac{w}{20}\) gallons of liquid passes.
    • In x seconds => \(\frac{w}{20}\) gallons pass through the drain.
    • Therefore, in 1 seconds= \(\frac{w}{(20x}\) gallons pass through the drain.
    • Therefore, in 1 minute=\(\frac{(w*60)}{(20*x)}\) = \(\frac{3w}{x}\) gallons pass through the drain.

Since \(\frac{3w}{x}\) gallons pass through the drain in 1 minute. Then, 1 gallon will pass through the drain in:
    • 1-gallon pass through the drain = \(\frac{x}{3w}\) minutes

Hence, y gallon will pass thorough the drain in \(\frac{xy}{3w}\)minutes.

Hence, the correct answer is option C.

Answer: C
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Re: A certain liquid passes through a drain at a rate of w/20 gallons ever   [#permalink] 09 Apr 2018, 23:38
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