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48% who voted were Women and 52% who voted are Men.
Since the values in the answer choices are not placed very closely, we can approximate 48% and 52% to 50% and 50% respectively.

50% of voters who voted = 53040 --> 100% of voters who voted = 53040*2 = 106080

Approximate 68% to 70%.
70% of eligible voters = 106080
100% of eligible voters = (106080*100)/70 = 151000 approx

Answer: B
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Bunuel
48% were women
Means men constituted 52%
Bunuel
The number of males exercising their franchise was 53,040.
So, 52% is 53040

100% is (53040/52)*100 =>1,02,000
Bunuel
In an election, 68% of the voters exercised their franchise..... How many eligible voters were there in all?
68% = 1,02,000

100% = 1,02,000/68 => 1,50,000

Hence answer is (B)
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voters who exercised their franchise = v of which 48 % were women and hence 52% were men.

given - The number of males exercising their franchise was 53,040

v * (68/100) * (52/100) = 53040

v = 150,000

Option B is correct.
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Bunuel
In an election, 68% of the voters exercised their franchise. Of these, 48% were women. The number of males exercising their franchise was 53,040. How many eligible voters were there in all?

(A) 102,000

(B) 150,000

(C) 234,000

(D) 252,000

(E) 288,000
Let total no of voters be 100
68 exercised their franchise.
48% of 68 were women; so 52% pf 68 were men... That is 53,040

Or, Total No of Voters is 53040/52% of 68*100 = 150000

Hence, answer will be (B) 150000
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Approximation :
68%=almost 2/3
48% =almost 1/2

For simplicity:
Total number of voter = 6x ( I.e. LCM OF 2 &3 from above).
Number of people who gave vote =6x*2/3=4x.; out of this 4x people, female =4x*1/2=2x remaining 2x=male who gave vote.
Given 2x =almost 50,000
So, 6x = almost 50,000*3=150,000.
B

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