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RSOHAL
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RSOHAL
Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of $1.80, how much money does Kim have?


(A) $1.00
(B) $1.12
(C) $1.20
(D) $1.32
(E) $1.40

Source: Test 55, S7, Q12, P28
K=(1+40/100)S
S=(1-20/100)P-------(a)
given S+P=1.8
add P on both sides of (a)
1.8=(1-20/100+1)P
P=1
so,S=0.8
As K=(1+40/100)S
putting S=0.8
gives K=1.12
Ans B
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RSOHAL
Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of $1.80, how much money does Kim have?


(A) $1.00
(B) $1.12
(C) $1.20
(D) $1.32
(E) $1.40

Source: Test 55, S7, Q12, P28
If ratios are involved (A has X percent more or less than B = a ratio), the moment we see a "counting number" we should pounce.

Sal and Phil have a combined total of $1.80. Thus: \((S+P)=$1.80\)

And: Sal has 20 percent less money than Phil: \(S = 0.80P\)
Substitute that value for \(S\). Now we have
\(0.8P+P=$1.80\)
\(1.8P=$1.80\)
\(P=\frac{$1.80}{1.8}=$1.00\)


Sal? \(S=0.80P=(0.8*$1.00)=$0.80\)

Kim? She has 40 percent more money than Sal.
\(K=1.4S\)
\(K=(1.4*$0.80)=$1.12\)


Answer B
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RSOHAL
Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of $1.80, how much money does Kim have?


(A) $1.00
(B) $1.12
(C) $1.20
(D) $1.32
(E) $1.40

Source: Test 55, S7, Q12, P28

Let x = Phil's money

Sal has 20 percent LESS money than Phil
So, Sal's money = (Phil's money) - (20% of Phil's money)
= x - (20% of x)
= x - 0.2x
= 0.8x

Kim has 40 percent more money than Sal
So, Kim's money = (Sal's money) + (40% of Sal's money)
= (0.8x) + (40% of 0.8x)
= (0.8x) + (0.4)(0.8x)
= 0.8x + 0.32x
= 1.12x



If Sal and Phil have a combined total of $1.80, how much money does Kim have?
We can write: 0.8x + x = 1.80
Simplify: 1.8x = 1.80
Solve: x = 1.80/1.8 = 1

We know that Kim's money = 1.12x
Since x = 1, we get: 1.12(1) = 1.12

Answer: B

Cheers,
Brent
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P =100,S= 80,K= 80*120/100= 112 ( assume).
P+S= 100+80= 180
So k = 1.8*112/180= 1.12

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Let Phil has $100.

=> Sal: 80 [20% less than Phil]

=> Kim: 80 * \(\frac{140 }{100}\) [40% less than Sal] = 112

The combined total of Sal + Phil: 180

When Phil had $100, Sal + Phil has $180. Therefore, Phil should have for $1, so that the combined total of Sal and Phil is $1.80

=> Kim: \(\frac{140 }{ 100}\) * Sam and Sam is \(\frac{80 }{ 100}\) * 1[Phil]

=> Kim: \(\frac{140 }{ 100}\) * \(\frac{80 }{ 100}\) * 1 = $1.12

Answer B
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