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Bunuel
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Bunuel
A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The question might look complex at first sight, but if we go ahead and solve, it is a straight forward selection probability quesiton

Given: Number of Men = x, Number of Women = y
2 men and 4 women are added.
Final number:
Men = x + 2, Women = y +4

Required: P(selection of 1 man)

P(selection of 1 man) = \(\frac{{total men}}{{total people}} = \frac{{x + 2}}{{x + y + 6}}\)
Option E
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