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Bunuel
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Bunuel
A woman has three blouses of different colors, three skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?

A. 8
B. 12
C. 16
D. 17
E. 18


If there are no restrictions, she could have 3 x 3 x 2 = 18 blouse-skirt-shoe combinations. Since the pink blouse and the green skirt together can pair with either one of the two pairs of shoes, the number of blouse-skirt-shoe combinations that consist of the pink blouse and the green skirt is 2. Therefore, she still has 18 - 2 = 16 blouse-skirt-shoe combinations she could wear.

Answer: C
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Dear Bunuel,

I really liked this question but I think that it would be better to clarify that the person should choose one of the pairs of shoes, otherwise we can have different combinations (lets say one red shoe in the left leg and one green shoe in the right is different from one green shoe in the left and one red in the right..sorry but I have seen many people doing this 😂).

Keep it up!
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Blouse: \(B_1, B_2, P_1\)(Pink)

Skirts: \(G_1, G_2, G_3\)(Green)

Shoes: \(Sh_1, Sh_2\)

=> \(P_1\) has two choices for Blouse and 2 choices for Shoes: 2 * 2 = 4

=> \(B_1\) has three choices for Blouse and 2 choices for Shoes: 3 * 2 = 6

=> \(B_2\) has three choices for Blouse and 2 choices for Shoes: 3 * 2 = 6

Total: 4 + 6 + 6 = 16

Answer C
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Blouse: \(B_1, B_2, P_1\)(Pink)

Skirts: \(G_1, G_2, G_3\)(Green)

Shoes: \(Sh_1, Sh_2\)

=> \(P_1\) has two choices for Blouse and 2 choices for Shoes: 2 * 2 = 4

=> \(B_1\) has three choices for Blouse and 2 choices for Shoes: 3 * 2 = 6

=> \(B_2\) has three choices for Blouse and 2 choices for Shoes: 3 * 2 = 6

Total: 4 + 6 + 6 = 16

Answer C

MathRevolution, thanks for the solution but I think you meant to write skirts instead of writing blouse.

Anyway thanks.
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