Last visit was: 24 Apr 2026, 11:12 It is currently 24 Apr 2026, 11:12
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,814
Own Kudos:
811,044
 [3]
Given Kudos: 105,873
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,814
Kudos: 811,044
 [3]
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
avatar
poojakaradgi
Joined: 11 Jan 2016
Last visit: 20 Feb 2021
Posts: 3
Given Kudos: 2
Location: India
GPA: 3.71
Posts: 3
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
davedekoos
Joined: 09 Jul 2013
Last visit: 07 Nov 2025
Posts: 96
Own Kudos:
Given Kudos: 11
Posts: 96
Kudos: 347
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
generis
User avatar
Senior SC Moderator
Joined: 22 May 2016
Last visit: 18 Jun 2022
Posts: 5,258
Own Kudos:
Given Kudos: 9,464
Expert
Expert reply
Posts: 5,258
Kudos: 37,728
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

A boat leaves point A heading directly across the river to point P, 120 yards away. A swift current immediately changes the boat’s direction, causing it to land instead at point B. How many yards is point B from the intended destination, P?

A. 40
B. 45
C. 60
D. \(40 \sqrt{3}\)
E. \(60 \sqrt{3}\)

Attachment:
2016-02-07_2125.png
∆ APB is a 30-60-90 special triangle
Vertex P = 90°, vertex A = 30°
Vertex B must = 60° (180° in a triangle)
We have a 30-60-90 triangle

Sides opposite those angles, respectively, are in ratio \(x: x\sqrt{3}: 2x\)

Length of BP, opposite the 30° angle = \(x\)

Side AP = 120 and is opposite the 60° angle
Length of 120 thus corresponds with \(x\sqrt{3}\)
Set them equal, solve for \(x\)
\(120=x\sqrt{3}\)
\(x=\frac{120}{\sqrt{3}}\)
\(x=(\frac{120}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}})=\frac{120\sqrt{3}}{3}=40\sqrt{3}\)


Point B is \(40\sqrt{3}\) yards from P

Answer D
Moderators:
Math Expert
109814 posts
Tuck School Moderator
853 posts