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zxcvbnmas
A certain animal shelter has 28 cats and 46 dogs. How many dogs must be adopted and taken away from the animal shelter so that 70 percent of the animals in the shelter will be cats?

A) 6
B) 12
C) 28
D) 34
E) 40

Assume number of dogs removed = x

Given:
28 = (70/100)*(28 + (46 - x)) = 0.7 * (74 - x)
40 = 74 - x
Or x = 34
Option D
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I plugged in on this question to find a solution.

Total Animals = 46+28 = 74

C.) 28
---> 74-28 = 46 animals left
28 cats/48 animals = 14/23 < 70% so I know more than 28 dogs have to leave

D.) 34
---> 74-34 = 40
28 cats/40 animals = 7/10 so the correct answer is D
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zxcvbnmas
A certain animal shelter has 28 cats and 46 dogs. How many dogs must be adopted and taken away from the animal shelter so that 70 percent of the animals in the shelter will be cats?

A) 6

B) 12

C) 28

D) 34

E) 40

let d=dogs to be adopted
(46-d)/28=3/7
d=34
D
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zxcvbnmas
A certain animal shelter has 28 cats and 46 dogs. How many dogs must be adopted and taken away from the animal shelter so that 70 percent of the animals in the shelter will be cats?

A) 6

B) 12

C) 28

D) 34

E) 40

There are a total of 28 + 46 = 74 animals. Let d denote the number of dogs to be removed so that 70% of the remaining animals are cats. We can create the equation:

28/(74 - d) = 7/10

280 = 7(74 - d)

280 = 518- 7d

7d = 238

d = 34

Alternative solution:

If the cats are 70% of the animals in the shelter and since the number of cats is 28, then the total number of animals in the shelter can only be 28/0.7 = 280/7 = 40. Thus there can be only 40 - 28 = 12 dogs in the shelter. Since there are currently 46 dogs, 46 - 12 = 34 dogs should be removed.

Answer: D
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