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Consider the number of nuts in larger can be 100
so the number of nuts in the smaller can which is half the size of the larger can the number of nuts is 50

30 % of nuts in larger can are peanuts = .3 *100 = 30
40 % of nuts in smaller can are peanuts = .4 * 50 = 20

Total number of peanuts both cans combined = 30 + 20 = 50
Total number of nuts in both cans combined = 100 + 50 = 150

% of peanuts in combined mix = \(\frac{50}{150}\) * 100 = 33 \(\frac{1}{3}\) %

correct answer - D
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In one can of mixed nuts, 30% is peanuts. In another can of mixed nuts that is one-half the size of the first one, 40% is peanuts. If both cans are emptied into the same bowl, what percentage of the mixed nuts in the bowl is peanuts?

A. 16 2/3%
B. 20%
C. 25%
D. 33 1/3%
E. 35%

let x=% of peanuts in bowl
.3*1+.4*.5=x*1.5
x=1/3=33 1/3%
D.
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(30%*100)+(40%*50)=(x*150)
=> x=50/150 = 33.33
Answer choice (D)

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