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Bunuel
For the positive integers x, x + 2, x + 4, x + 7, and x + 12, the mean is how much greater than the median?

A. 0
B. 1
C. 2
D. 4
E. 7


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Mean: Average of all the numbers. (Sum of all the elements of the set divided by the number of elements in the set)
Median: Arrange the elements of the set in increasing order. If the number of terms is odd, the middle term is the median. If the number of terms is even, the average of middle two terms is the median

Median = x + 4
Mean = (5x + 25)/5 = x + 5

Therefore mean is 1 greater than the median.
Option B
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Mean = (x + x+2 + x+4 + x+7 + x+12)/5
=(5x+25)/5
=x+5

Median = x+4
Thus Mean - Median = x+5 - x+4
=1

Answer = B
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Bunuel
For the positive integers x, x + 2, x + 4, x + 7, and x + 12, the mean is how much greater than the median?

A. 0
B. 1
C. 2
D. 4
E. 7


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Hi,
We can further simplify x, x + 2, x + 4, x + 7, and x + 12 to 0, 2, 4, 7, 12, as x is common to all five terms..
MEAN of 0, 2, 4, 7, 12= (0+2+4+7+12)/5=5
median=4..
difference=5-4=1..
B
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MEAN
mean = [(x) + (x + 2) + (x + 4) + (x + 7) + (x + 12)/5
= (5x + 25)/5
= x + 5

MEDIAN
The 5 values are already arranged in ASCENDING order {x, x + 2, x + 4, x + 7, x + 12}
So, the median = the middle value = x + 4

The mean is how much greater than the median?
In other words x + 5 is how much greater than the x + 4?
Answer = (x + 5) - (x + 4)
= 1

Answer: B

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Bunuel
For the positive integers x, x + 2, x + 4, x + 7, and x + 12, the mean is how much greater than the median?

A. 0
B. 1
C. 2
D. 4
E. 7


Let’s first calculate the mean of the 5 values:

(x + x + 2 + x + 4 + x + 7 + x + 12)/5 = (5x + 25)/5 = x + 5

The median is x + 4.

So the difference is:

x + 5 - (x + 4) = 1

Answer: B
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