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Bunuel
How many ways can Jason sit with his five friends in a row of six seats with an aisle on either side of the row, if Jason insists on sitting next to one of the aisles?

A. 120
B. 240
C. 360
D. 540
E. 720

Six seats are _ _ _ _ _ _

Jason can sit on either first seat in 2 way

Remaining 5 people have 5 chairs left so they can sit in 5*4*3*2*1 = 5! = 120 ways

Total ways of all of them to sit = 2*5! = 2*120 = 240 ways

Answer: Option B
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Official explanation

Because Jason must sit on either aisle, there are two places he can sit. And for each of those two seats, there are five friends left for five seats, making 5! ways to arrange them. So the answer is 2 * 5!, which is 240
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Bunuel
How many ways can Jason sit with his five friends in a row of six seats with an aisle on either side of the row, if Jason insists on sitting next to one of the aisles?

A. 120
B. 240
C. 360
D. 540
E. 720
There are 6 seats (With 2 Isle Seats) and 6 persons ...

Jason can seat in 2 ways (in either of the isle Seats) , and we are left with 5 persons and 5 seats which can be done in 5! ways...

SO, Total no of possible ways is 2*5! = 240, Answer must be (B)
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Bunuel
How many ways can Jason sit with his five friends in a row of six seats with an aisle on either side of the row, if Jason insists on sitting next to one of the aisles?

A. 120
B. 240
C. 360
D. 540
E. 720

There are 2 ways to choose an aisle and there are 5!=120 ways to choose arrangement of 5 friends.

Total ways =2×120=240

IMO B

Posted from my mobile device
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Bunuel
How many ways can Jason sit with his five friends in a row of six seats with an aisle on either side of the row, if Jason insists on sitting next to one of the aisles?

A. 120
B. 240
C. 360
D. 540
E. 720

Since Jason must sit in an aisle seat, we have the following 2 situations:

J _ _ _ _ _ = 120 ways
_ _ _ _ _ J = 120 ways

120 + 120 = 240 ways

Answer is B.
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