Each student at a certain business school is assigned a 4-digit studen

Question

Each student at a certain business school is assigned a 4-digit student identification number. The first digit of the identification number cannot be zero, and the last digit of the identification number must be prime. How many different student identification numbers can the school create?

A. 9,000
B. 3,600
C. 2,700
D. 2,592
E. 1,944

A. 9,000
B. 3,600
C. 2,700
D. 2,592
E. 1,944

chetan2u · Answer

Hi,
these are simple Combinations problems..
 But the most important point here is to reread if the combination is of different digits or the same digit can be repeated..
 
Here, there is no restriction..
Let the number be ABCD..
 1) A can be any of the 10 digits, 0-9, except 0, so 9 ways..
2) B and C can be any of the 10 digits, so 10 ways each..
3) D is a prime number, so 2,3,5,7 fit in--- 4 ways..

Total ways= 9*10*10*4=3600
B

TeamGMATIFY · Answer

The identification number is of the form _ _ _ _

1. First digit cannot be 0
2. Middle digits can be anything
3. Last digit has to be prime - 2, 3, 5, 7

We can have the following number of possibilities for each space
__ __ __ __
 9 10 10 4 
Total cases = 3600
Option B

sowragu · Answer

__ __ __ __
9 10 10 4

9*10*10*4 = 3600.

Just for understanding, If the same question mentioned as no repetition allowed, then it would be

Always start with the most restrictive clause, which number should end with a prime - 4 options are available.
__ __ __ __ 
 4

The next restrictive clause is the number should not start with a zero. Already one number has been placed in the unit position and now we cant include zero to. So we have remaining 8 numbers to put in first place.

__ __ __ __
8 4

Remaining two positions has not restrictions. Hence we have 8 numbers (including zero) for one position and 7 numbers for the other.

__ __ __ __
8 8 7 4

= 8*8*7*4

mejia401 · Answer

Using the slot method, there are four choices so four slots.

The first restriction is that the number must not begin with zero, thus 9 choices.
The follow two slots, or digits, do not have restrictions, thus 10 choices each.
The last slot must be a prime number, thus four choices (2,3,5, and 7).

Therefore, 
 9 * 10 * 10 * 4 = 3600

ScottTargetTestPrep · Answer

There are 9 possible options for the first digit, 10 for the second digit, 10 for the third digit, and 4 for the last digit, since the prime digits are 2, 3, 5, and 7.

Thus, the number of codes that can be created is 9 x 10 x 10 x 4 = 3600.

Answer: B

bumpbot · Answer

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Each student at a certain business school is assigned a 4-digit studen

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