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Bunuel
Each student at a certain business school is assigned a 4-digit student identification number. The first digit of the identification number cannot be zero, and the last digit of the identification number must be prime. How many different student identification numbers can the school create?

A. 9,000
B. 3,600
C. 2,700
D. 2,592
E. 1,944

__ __ __ __
9 10 10 4

9*10*10*4 = 3600.

Just for understanding, If the same question mentioned as no repetition allowed, then it would be

Always start with the most restrictive clause, which number should end with a prime - 4 options are available.
__ __ __ __
4

The next restrictive clause is the number should not start with a zero. Already one number has been placed in the unit position and now we cant include zero to. So we have remaining 8 numbers to put in first place.

__ __ __ __
8 4

Remaining two positions has not restrictions. Hence we have 8 numbers (including zero) for one position and 7 numbers for the other.

__ __ __ __
8 8 7 4

= 8*8*7*4
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Using the slot method, there are four choices so four slots.

The first restriction is that the number must not begin with zero, thus 9 choices.
The follow two slots, or digits, do not have restrictions, thus 10 choices each.
The last slot must be a prime number, thus four choices (2,3,5, and 7).

Therefore,
\(9 * 10 * 10 * 4 = 3600\)
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Bunuel
Each student at a certain business school is assigned a 4-digit student identification number. The first digit of the identification number cannot be zero, and the last digit of the identification number must be prime. How many different student identification numbers can the school create?

A. 9,000
B. 3,600
C. 2,700
D. 2,592
E. 1,944

There are 9 possible options for the first digit, 10 for the second digit, 10 for the third digit, and 4 for the last digit, since the prime digits are 2, 3, 5, and 7.

Thus, the number of codes that can be created is 9 x 10 x 10 x 4 = 3600.

Answer: B
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