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Area of Triangle = \(\frac{b*h}{2}\)

Desired Ratio = \(\frac{b*h}{2}\)*\(\frac{2}{(b*x*h*x)}\) = \(\frac{2bh}{2bhxx}\) = \(\frac{1}{x^2}\)

Answer: A
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Given: Each side is of triangle ABC= x* the corresponding side of triangle XYZ.
So,
Area of triangle ABC= 1/2.b.h.
Area of triangle XYZ= 1/2. (xb).(xh).

Therefore area of triangle XYZ to that of fraction of the area of triangle ABC = 1/x^2.

Answer: A

Guys this is my first post in this forum. Kindly let me know for any modifications. :)
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↧↧↧ Weekly Video Solution to the Problem Series ↧↧↧



Theory: If Two Triangles are Similar then ratio of their Areas is equal to square of ratio of their sides

Given that Right △ ABC and △ XYZ are similar and each side of triangle ABC is x times the corresponding side of triangle XYZ.

Let side of △ XYZ be X => Corresponding side of △ ABC = x*X = xX

=> \(\frac{Area Of △ ABC }{ Area Of △ XYZ} = (\frac{xX }{ X})^2\) = \(x^2\)
=> Area of △ XYZ = \(\frac{1}{x^2}\) * Area of △ ABC

So, Answer will be A
Hope it helps!

Watch the following video to learn the Basics of Similar Triangles

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