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18 Mar 2016, 00:15
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B
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Difficulty:
15%
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Question Stats:
85% (00:48) correct
15%
(01:50)
wrong
based on 58
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In May, the grounds keeper at Spring Lake Golf Club built a circular green with an area of 100π square feet. In August, he doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
A) 1000π
B) 400π
C) 200π
D) 200
E) 20π
A) 1000π
B) 400π
C) 200π
D) 200
E) 20π
18 Mar 2016, 01:54
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Current area = pi * r^2 = 100 * pi --> r = 10
Radius is doubled --> r = 20. New area = 400 * pi
Answer: B
Radius is doubled --> r = 20. New area = 400 * pi
Answer: B
bethebest
Joined: 01 Mar 2014
Last visit: 24 Mar 2017
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Schools: Tepper '18
26 Mar 2016, 07:17
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Vyshak
Shouldn't the total area of the 'RENOVATED' green not be equal to the green area added?? which means 4oopi - 100pi = 300pi
But thats not even an option..!!
