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Difficulty:
5%
(low)
Question Stats:
89% (00:54) correct
11%
(01:13)
wrong
based on 160
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A straight line has a slope of 1/2 and a y-intercept of -2. On this line, what is the x-coordinate of the point whose y-coordinate is 10?
1. (8)
2. (12)
3. (13)
4. (16)
5. (24)
1. (8)
2. (12)
3. (13)
4. (16)
5. (24)
Hi Guys
Coordinate geometry is a struggling area for me. Purpose of below discussion is to understand a simple question in geometry way, a step ahead of algebraic way.
Answer: Using equation == y=mx+c; we get x = 24
Now, the same question was to answered this way. If intercept is -2 and X intercept was X. Then the slope means the that (X+2, -1) and thus (X+13, 10). Yet that's what I get out of this. I fail to understand how to make this X+13 = 24 now. Kindly help!
Coordinate geometry is a struggling area for me. Purpose of below discussion is to understand a simple question in geometry way, a step ahead of algebraic way.
Answer: Using equation == y=mx+c; we get x = 24
Now, the same question was to answered this way. If intercept is -2 and X intercept was X. Then the slope means the that (X+2, -1) and thus (X+13, 10). Yet that's what I get out of this. I fail to understand how to make this X+13 = 24 now. Kindly help!
10 May 2016, 04:58
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ruchi857
Hi,
I'll try to solve the way you wanted ... IF I have understood it well..
1) when y intercept is -2, x=0...... so one point is (0,-2)..
2) we are looking for x coord when y is 10..... let it be (x, 10)..
3) slope is -1/2..
so\(\frac{y_2-y_1}{x_2-x_1} = -\frac{1}{2}\)..
\(\frac{10-(-2)}{x-0} = -\frac{1}{2}\).................. x = 12*2 = 24..
I hope this ws your query
