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Bunuel
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Given : ab + a is always odd. the expression can be simplified as :

ab + a = a(b+1) = odd. Only a multiplication of an odd to another odd number will yield an odd. => odd * odd = odd.

Thus, a= odd, and b+1 = odd => b = even. Hence B.
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Bunuel
The expression ab+a is odd when the a and b are integers. Which of the following expressions must be even?

(A) a
(B) b
(C) a + b
(D) ab - a
(E) a + b^2

a b ab a ab+a
e o e e e
o e e o o (2nd line)
e e e e e
o o 0 0 e

Only the 2nd line gives us an odd value so "a" has to be odd and "b" has to be even

Testing all the options with these inputs will give us option B as the answer.
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A very quick solution:

ab + a = a (b + 1)
For the above equation to be odd, both a and (b+1) must be odd
If b+1 must be odd, b must be even

Answer: B
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