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Find: sum of odd integers from 101 to 200 inclusive

Formula: We know that the sum of the first odd integers n is: \(n^2\), where n is the number of odd terms

Solution:
1) Number of odd integers from 1 to 101: 100 / 2 + 1 = 51
2) Sum of odd integers from 1 to 101: \(51^2\) = 2601
3) Number of odd integers from 1 to 200: 200 / 2 = 100
4) Sum of odd integers from 1 to 200: \(100^2\) = 10000
5) Sum of odd integers from 101 to 200: 10,000 - 2,601 = 7399

Where did I make a mistake that I don't get 7,500 exactly?
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Bunuel
The sum of the first 50 positive even integers is 2,550. What is the sum of the odd integers from 101 to 200, inclusive?

(A) 5,050
(B) 7,500
(C) 10,500
(D) 15,000
(E) 19,600





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

[email protected]
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You missed to include the first odd integer, it will be 50^2 = 2500, not 51^2.
fantaisie
Find: sum of odd integers from 101 to 200 inclusive

Formula: We know that the sum of the first odd integers n is: \(n^2\), where n is the number of odd terms

Solution:
1) Number of odd integers from 1 to 101: 100 / 2 + 1 = 51
2) Sum of odd integers from 1 to 101: \(51^2\) = 2601
3) Number of odd integers from 1 to 200: 200 / 2 = 100
4) Sum of odd integers from 1 to 200: \(100^2\) = 10000
5) Sum of odd integers from 101 to 200: 10,000 - 2,601 = 7399

Where did I make a mistake that I don't get 7,500 exactly?
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